Deriving Velocity For Projectiles

Click For Summary
To determine the required muzzle velocity for a projectile launched at a 30-degree angle to hit a target 100 meters away, basic projectile motion equations can be applied. Without air resistance, the initial velocity can be calculated using the formula for range, which incorporates the angle of launch and gravitational acceleration. When factoring in air resistance, specifically for a droplet shape, the calculations become more complex, requiring drag coefficient considerations. The discussion emphasizes the need for understanding both the physics principles and the mathematical formulas involved. Accurate calculations are essential for achieving the desired projectile motion in both scenarios.
jerromyjon
Messages
1,244
Reaction score
189
I have a projectile that can only launch at 30 degrees and a target exactly 100m away at the same elevation on flat ground with 1g (9.8m/s2 meters per second per second?) What velocity without (then with) air resistance would the "muzzle velocity" need to be? (with a droplet shape for resistance)

I can't even figure out how to get started with a minimum mass and velocity to "just make it".
 
Physics news on Phys.org
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K