Describing behavior on each side of a vertical asymptote

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SUMMARY

The vertical asymptotes of the function F(x) = (3 - x) / (x^2 - 16) are located at x = 4 and x = -4. As the function approaches these asymptotes, the behavior is defined by limits: F(x) approaches +∞ as x approaches -4 from the left and -∞ from the right, while it approaches +∞ as x approaches 4 from the left and -∞ from the right. This analysis confirms the function's behavior near its vertical asymptotes.

PREREQUISITES
  • Understanding of vertical asymptotes in rational functions
  • Knowledge of limits in calculus
  • Ability to factor quadratic expressions
  • Familiarity with the concept of infinity in mathematical analysis
NEXT STEPS
  • Study the concept of limits in calculus, focusing on one-sided limits
  • Learn how to identify and analyze vertical asymptotes in rational functions
  • Explore the behavior of functions near horizontal asymptotes
  • Practice with additional examples of rational functions and their asymptotic behavior
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in understanding the behavior of rational functions near vertical asymptotes.

Jacobpm64
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Find the vertical asymptotes of the graph of F(x) = (3 - x) / (x^2 - 16)

ok if i factor the denominator.. i find the vertical asymptotes to be x = 4, x = -4.

The 2nd part of the problem asks:
Describe the behavior of f(x) to the left and right of each vertical asymptote.. I'm not sure what i need to write for this.
 
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It's asking for what happens as the function appraches the asymptotes from the left and the right, does it go to infinity - what?

You can use limits to find out.
 
ahh thanks.. so...

f(x) approaches +inf as it approaches x = -4 from the left...
f(x) approaches -inf as it approaches x = -4 from the right...
f(x) approaches +inf as it approaches x = 4 from the left...
f(x) approaches -inf as it approaches x = 4 from the right...

correct?
 
Correct. :smile:
 

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