How Close to Speaker B Must You Be for Destructive Interference at 172 Hz?

In summary: Remember that the distance between the two speakers is the same as the wavelength.In summary, to find the closest distance ##d_B## that allows for destructive interference, we can use the equation ##\frac{d_B - d_A}{\lambda} = (n+\frac{1}{2})##, where ##d_A = 8##m and the wavelength ##\lambda## is equal to the distance between the two speakers. The solution is ##d_B = 1##m.
  • #1
sreya
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0

Homework Statement



Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 172 Hz. You are 8.00 m from speaker A. Take the speed of sound in air to be 344 m/s.

What is the closest you can be to speaker B and be at a point of destructive interference?
Express your answer in meters.

Homework Equations



[itex] f = \frac{v}{\lambda}[/itex]
[itex] \frac{\Delta L}{\lambda} = .5,1.5,2.5,...[/itex]

The Attempt at a Solution



[itex] \lambda = 344/172 = 2 [/itex]

[itex] 1/2 = .5 => Ans:[/itex]1m

The odd thing is that it tells you the distance you are from A but wants to know how close you can get to B but you don't know the distance between the two.

The answer is 1, since that would give you 1/2 = .5 but that seems like to me that you're 1m away from A, since we don't know how close we are to B
 
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  • #2
It might help to use more explicit notation for the various distances. Let ##d_A## be your distance from speaker A and ##d_B## your distance from speaker B. You are given ##d_A = 8##m, but let's keep using the symbol ##d_A##. We can plug in numbers later.

You wrote ##\frac{\Delta L}{\lambda} = .5, 1.5, 2.5, ...##.

You can write this as ##\frac{\Delta L}{\lambda} = (n+\frac{1}{2})## where ##n = 0, 1, 2, ...##.

Can you express this equation in terms of the symbols ##d_A## and ##d_B##?
 

What is destructive interference?

Destructive interference is a phenomenon that occurs when two or more waves of equal frequency and amplitude meet and cancel each other out, resulting in a decrease or complete elimination of the wave's amplitude at certain points.

How does destructive interference differ from constructive interference?

Destructive interference occurs when two waves are out of phase, meaning their peaks and troughs line up and cancel each other out. In contrast, constructive interference occurs when two waves are in phase, meaning their peaks and troughs align and combine to create a larger amplitude.

What causes destructive interference?

Destructive interference is caused by the superposition of two or more waves that are of equal frequency and amplitude, but have opposite phase angles. This can happen when two waves are traveling in opposite directions, or when they are reflected off of a boundary like a wall or mirror.

How is destructive interference used in real-world applications?

Destructive interference is used in many different applications, such as noise-cancelling headphones, where sound waves are cancelled out by creating an opposite wave with the same amplitude. It is also used in optical coatings to reduce glare and in seismic exploration to identify underground oil and gas deposits.

Can destructive interference occur in other types of waves besides sound and light?

Yes, destructive interference can occur in any type of wave, including water waves, seismic waves, and electromagnetic waves. As long as two waves with equal frequency and amplitude meet at certain points with opposite phase angles, destructive interference can occur.

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