1. The problem statement, all variables and given/known data Two boys have a "hang time" contest on their skateboards. At a speed of 5.0 m/s, they both jump straight up and then land on their moving skateboards. The first boy goes a horizontal distance of 7.5 m before he lands, while the second boy goes 6.0 m before he lands. a) How long was each boy in the air b) How high did each boy jump? (Hint: Separate the horizontal and vertical motions. Time is the same for both) 2. Relevant equations d = vi X t + 1/2a X t2 3. The attempt at a solution a) first boy: 7.5/5 = 1.5 s second boy: 6/5 = 1.2 s b) d = 5 X 1.5 + ½(-9.8) X 1.52 d = 7.5 + (-3775) d = 3.725 m d = 5 X 1.2 + ½(-9.8) X 1.22 d = 6 + (-7.056) d = (-1.056) m I don't know if I'm using the wrong formula or a wrong value..... possibly because I calculated the answer to the first question incorrectly?