Determine the maximum current discharged from a battery

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The discussion focuses on understanding how manufacturers determine the maximum current a battery can discharge, emphasizing that this is influenced by the battery's internal resistance and chemistry. It clarifies that while Ohm's Law applies, the maximum current, or short circuit current, is limited by internal resistance, and practical current ratings depend on battery design and conditions. The conversation highlights that a typical 9V battery can only deliver around 3-4A, with performance decreasing over time due to energy storage limits. Participants note that high currents can damage batteries, and the internal resistance may vary under different conditions. Ultimately, the key takeaway is the importance of not applying Ohm's Law blindly, especially under high current scenarios.
roonaldo17
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Hi, I'm not sure about how manufacturers calculate the maximum constant current that a battery can discharge. I understand that a battery capacity rating is given by 20hrs multiplied by the maximum current value.

I learned also that by shorting a 9V battery of internal resistance 0.01ohms, we will not get 900A of current running through a circuit, hence ohm's law does not apply.

I'm quite sure this should be related to the energy stored within the battery, but due to the limits of my knowledge the only formula I know is energy= V x I x T. I can't put a value for time in this formula though!
 
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I learned also that by shorting a 9V battery of internal resistance 0.01ohms, we will not get 900A of current running through a circuit, hence ohm's law does not apply.

A battery is usually thought of as an ideal voltage source (no resistance) in series with a resistance called the "internal resistance". Ohm's Law DOES apply. I don't know where you got the quote from, but I don't think it is quite right. Perhaps there is some picky little difference such as the voltage on the battery being a little more than 9 Volts when no current is drawn. I just measured one with a Voltmeter and it says 9.5 Volts (no load). So I would think of it as a 9.5 Volt ideal battery in series with some internal resistance and I would apply Ohm's Law. By hooking it up to a known resistance and measuring the voltage or current, I could calculate the internal resistance or anything else including the power supplied by the battery or energy released over a period of time.
 
roonaldo17 said:
I understand that a battery capacity rating is given by 20hrs multiplied by the maximum current value.
That's really more of a guideline that you should slow charge a battery at 1/20 of it's capacity.

I learned also that by shorting a 9V battery of internal resistance 0.01ohms, we will not get 900A of current running through a circuit, hence ohm's law does not apply.
You will very briefly until the battery is destroyed.
Fortunately small alkaline batteries have a higher internal resistance. But lead acid do have internal resistances this low - you can get a current of 1000A from a car battery if you for example short the terminals together with a spanner/wrench !

I'm quite sure this should be related to the energy stored within the battery, but due to the limits of my knowledge the only formula I know is energy= V x I x T. I can't put a value for time in this formula though!
The maximum current, known as the short circuit current, is only limited by the internal resistance. The maximum practical current will depend on the design of the battery, the temperature, cooling etc and will be given by the maker.
 
Sorry if I weren't making good sense here..I'm a freshman currently doing my 1st electrical engineering course.

Because I learned that ohm's law is only an approximation, in fact variation of current with voltage across an element is not always linear. Also the other day my prof was saying sth like " in fact a typical 9V battery can only deliver a maximum of 3-4A, and after a few seconds the current supply will decrease. "

I could not understand how he calculate that. And I thought the max current perhaps vary with the time that we intend to use the battery? (again from energy = V x I x T)
 
he was referring to this battery:

" a typical small 9V battery (2010) "

and telling us we would not get 900A if we were to short it
 
Ohm's law is correct - for an ohmic resistor!
Batteries are normally modeled in a circuit as a perfect (unchanging) voltage in series with a resistor (the internal resistance) this gives you the correct answer at current where the battery is still working. ultimately if you take too much current you will be limited by the chemistry of the battery and it will either stop giving you any more current or be damaged (depending on the type).
The internal resistance for very high currents or very short times might be different.

I'm surprised that a PP3 has such a low internal resistance - they are normally made from 6x1.5V AAAA cells in series which should each have R=0.2 or so.

See http://data.energizer.com/PDFs/BatteryIR.pdf
 
You're right, it should be the chemistry of the battery that limits the current.
Was trying to understand how to calculate such a current, trying too hard I guess..

The main thing I've learned is not to apply ohm's law blindly, as ohmic resistors can become non-ohmic subjected to high current/voltage conditions.
And thanks a lot :)
 
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