Determine the reverse saturation current for the diode

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SUMMARY

The reverse saturation current (Is) for the diode is calculated using the formula Id = Is(e^(VD/(h*25mV))-1). Given a diode current (Id) of 10mA, a voltage source (VS) of 5V, and a resistance (R) of 360Ω, the calculated reverse saturation current is 4.43x10^-12 A. The user encountered difficulties in determining the correct voltage drop (VD) after calculating Is, resulting in an incorrect value of approximately 662V instead of the expected 0.7V.

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  • Understanding of diode equations and characteristics
  • Familiarity with thermal voltage (VT) calculation, VT = kT/q
  • Knowledge of exponential functions in electrical engineering
  • Basic circuit analysis involving Ohm's Law
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koop011
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Determine the reverse saturation current for the diode below, given that VS = 5V, R = 360Ω produces a diode current of 10mA. Use h = 1.3 and VT = kT/q = 25mV.
WMPfQgx.jpg


I believe this is the formula needed.
Id = Is(e^(VD/(h*25mV))-1)

The problem I had was I've done several questions similar to this but I was always given the Is (the reverse saturation I believe). But this time it's the reverse.

I've tried to solve this by retracing from

10mA = Is(e^(0.7/(1.3*25mV))-1)

(0.7V was supplied one time, since i needed to find other VD when Id(mA) = 1, 5, 10, 20)

and the answer I got was 4.43x10^-12

Seemed right until I put the numbers back in and tried getting the VD. I think i got somewhere around 662V or something instead of 0.7.

Any idea how to go about this?

Much thanks in advance!
 
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koop011 said:
the answer I got was 4.43x10^-12
That's the value of IS that I calculate.
 

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