Determine the velocity of an electron orbiting an atom ?

Victor Frankenstein
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Is it possible to determine the velocity of an electron orbiting an atom ?

Would the velocity be greater for an atom with more mass ?
 
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It is possible to determine some eigenvalue of momentum for an electron in an atom, but you can't take that and do celestial mechanics with it, because the sharpness in knowing the velocity comes at the cost of vagueness in knowing the position. You can't have a classical orbit without knowing both, and the uncertainty principle says you can't know both accurately at the same time.

Because of uncertainty and its pal the exclusion principle, electrons in atoms arrange themselves in shells, the number of shells increasing through the rows of the periodic table. The outer shells are at a higher energy level than the inner ones, but again there are no Kepler's laws to resort to in quantum land.
 
Though it´s not appropriate to say ¨the velocity¨ of the electrons in an atom, there´s still semi-classical analog: probability flow density. Also, you can mimic the conception of velocity as p/m, where p is the momentum operator, take the expectation value of p/m, you can get a semi-classical velocity.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
Not an expert in QM. AFAIK, Schrödinger's equation is quite different from the classical wave equation. The former is an equation for the dynamics of the state of a (quantum?) system, the latter is an equation for the dynamics of a (classical) degree of freedom. As a matter of fact, Schrödinger's equation is first order in time derivatives, while the classical wave equation is second order. But, AFAIK, Schrödinger's equation is a wave equation; only its interpretation makes it non-classical...
Thread 'Lesser Green's function'
The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...

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