Determine the work and heat transfer

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SUMMARY

The discussion focuses on calculating work and heat transfer for steam undergoing a polytropic process in a piston-cylinder assembly. Key parameters include initial pressure (p1 = 100 lbf/in²), final pressure (p2 = 40 lbf/in²), initial specific volume (v1 = 4.934 ft³/lb), final specific volume (v2 = 11.04 ft³/lb), and internal energy values (u1 = 1136.2 Btu/lb, u2 = 1124.2 Btu/lb). The work done is derived using the equation W = (p2V2 - p1V1)/(1-n), with n calculated as 1.14. The conversion from ft-lbf to BTU is necessary to express work in BTU/lb, and the first law of thermodynamics is applied to determine heat transfer.

PREREQUISITES
  • Understanding of polytropic processes in thermodynamics
  • Familiarity with the first law of thermodynamics
  • Knowledge of unit conversions between ft-lbf and BTU
  • Ability to perform integration in thermodynamic equations
NEXT STEPS
  • Study the derivation of polytropic process equations in thermodynamics
  • Learn about unit conversion techniques between different energy units
  • Explore the application of the first law of thermodynamics in various processes
  • Investigate the significance of specific volume in thermodynamic calculations
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Students and professionals in mechanical engineering, particularly those focusing on thermodynamics and energy transfer processes in steam systems.

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Homework Statement



Steam in a piston-cylinder assembly undergoes a polytropic process. Kinetic and potential energy effects are negligible. For the process, determine the work and heat transfer, each in Btu per lb of steam.

p1 = 100 lbf/in2
p2 = 40 lbf/in2
v1 = 4.934 ft3/lb
v2 = 11.04 ft3/lb
u1 = 1136.2 Btu/lb
u2 = 1124.2 Btu/lb

Homework Equations



ΔE = Q - W

W = ∫v1v2pdV

The Attempt at a Solution



Since the process is polytropic, PVn = constant = p1V1n = p2V2n

Thus, W = ∫v1v2(constant/Vn)dV = (p2V2 - p1V1)/(1-n)

I used the relation p1V1n = p2V2n to find n, which gives me n = 1.14

Then, my plan is to plug the numbers into my integrated work function, but I am extremely confused on the units of this and I'm not really sure if I'm even working in the right direction. Basically I've gotten stuck at this point. Any help would be much appreciated.
 
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Your equation for the work is correct. To get the work in BTU/lb, you need to first get it in ft-lbf/lb, and then convert the ft-lbf to BTU. Then you use the first law of thermo to get the heat, since you already know both W and ΔE.

Chet
 

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