Which is larger: 2^500 or 5^200?

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To determine which is larger between 2^500 and 5^200, the discussion explores rewriting the expressions for comparison. The transformation to 4^250 versus 5^200 suggests that 4^250 appears larger, but further mathematical justification is needed. Participants suggest dividing the two numbers to find a common base for clearer comparison. A proposed method involves manipulating the expressions to prove that the numerator exceeds the denominator. Ultimately, a rigorous mathematical approach is necessary to conclusively determine the larger value.
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Homework Statement


Which is bigger 2^500 or 5^200


Homework Equations


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The Attempt at a Solution


Well I got to 2^2^250 -> 4^250 vs 5^200... by the looking at it 4^250 is bigger but I can't just say it looks bigger... There are lots of these that I can't get on a common base, so if anyone can point me to the right direction I'll give lots of love.
 
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divide the two numbers.
come to a form of (a/b^n)^k * a^k = (a*(a/b^n))^k
prove that a/b^n > 1/a
from that you can easily proove that the numerator is bigger than the denominator
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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