Determining certain mass of a Hydrate

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To determine the mass of the anhydrous salt from a hydrate weighing 5.82g with 62.9% water content, first calculate the mass of water by multiplying 5.82g by 0.629, resulting in approximately 3.66g of water. The remaining mass, which is 5.82g minus 3.66g, gives the mass of the anhydrous salt. This results in a mass of about 2.16g for the anhydrous salt. The calculations clarify the relationship between the hydrate's total mass and its components. Understanding these proportions is essential for accurate chemical analysis.
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5.82g of a Hydrate is taken. If 62.9% of H2O is contained in the Hydrate what is the mass of the anhydrous salt?

so far i got 62.9% and 37.1% and i was thinking about getting H2O in grams but i don't know how
 
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Larrytsai said:
5.82g of a Hydrate is taken. If 62.9% of H2O is contained in the Hydrate what is the mass of the anhydrous salt?

so far i got 62.9% and 37.1% and i was thinking about getting H2O in grams but i don't know how

Well, if you multiply 0.371 by 5.82, I believe that would give you the mass of the anhydrous salt since 0.629 x 5.82 is the mass of the water contained in the hydrate.
 
Snazzy said:
Well, if you multiply 0.371 by 5.82, I believe that would give you the mass of the anhydrous salt since 0.629 x 5.82 is the mass of the water contained in the hydrate.

O right i got it now thnx alot
 
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