Determining Frequencies that Exist in a Signal

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The discussion focuses on determining the frequencies present in the signal s(t) defined by the modulation equation s(t) = Acos(2∏f₁t) * Bcos(2∏f₂t). The derived expression shows that the signal can be expressed as a combination of two cosines, leading to frequencies f1 + f2 and f1 - f2. It clarifies that in double-sideband suppressed-carrier modulation, the frequencies f1 and f2 do not appear in the final result, only their sums and differences. The correct frequencies present in the signal are thus f1 + f2 and |f1 - f2|, emphasizing the nature of the modulation type. Understanding this distinction is crucial for accurately analyzing the modulation scheme.
Kleric
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Homework Statement


Using trig identities from a calculus book or other, write out the results to the following modulations. State which frequencies exist in the signal s(t).

Homework Equations


a) s(t) = Acos(2∏f₁t) * Bcos(2∏f₂t)

The Attempt at a Solution


cos(s) * cos(t) = cos (s + t)/2 + cos (s – t)/2

s(t) = ((AB)/2)*(cos(2∏t(f1 + f2)) + cos(2∏t(f1 - f2)))

What I don't quite understand is the part that asks to state which frequencies exist in the signal. I understand that in modulation, half of the signal is shifted to the right by f2, then the other half of the signal is shifted to the left by f2. Which would make the answers f2 and -f2.

According to the answer it should be f1, f2, |f2-f1|, f1+f2.
 
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Your maths looks right.

s(t) = ((AB)/2)*(cos(2∏t(f1 + f2)) + cos(2∏t(f1 - f2)))

is similar to the sum of two waves..

= Cos(2∏Fusbt) + Cos(2∏Flsbt)

when

Fusb = upper side band frequency = f1+f2
Flsb = lower side band frequency = f1-f2
 
In radio signal f2 would be the speech/music and f1 the RF carrier. Since speech and music are not pure tones the result is a band of frequencies either side of the carrier as shown in the diagram

http://en.wikipedia.org/wiki/Sideband
 
Kleric said:

Homework Statement


Using trig identities from a calculus book or other, write out the results to the following modulations. State which frequencies exist in the signal s(t).

Homework Equations


a) s(t) = Acos(2∏f₁t) * Bcos(2∏f₂t)


The Attempt at a Solution


cos(s) * cos(t) = cos (s + t)/2 + cos (s – t)/2

s(t) = ((AB)/2)*(cos(2∏t(f1 + f2)) + cos(2∏t(f1 - f2)))

What I don't quite understand is the part that asks to state which frequencies exist in the signal. I understand that in modulation, half of the signal is shifted to the right by f2, then the other half of the signal is shifted to the left by f2. Which would make the answers f2 and -f2.

According to the answer it should be f1, f2, |f2-f1|, f1+f2.

The answer is wrong. f1 and f2 do not exist in the product, just the sums and differences, just as you have derived.

In ordinary amplitude modulation (think radio broadcast AM), , they do, but you have what is called "double-sideband, suppressed-carrier" modulation. Think of f1 as the carrier and f2 as the modulation, then you can see why it's called what it is.
 

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