Determining LED light intensity from its radiant power

Click For Summary
SUMMARY

This discussion focuses on converting the radiant power of LEDs, specifically 0.7mW, into light intensity measured in W/cm². The key method involves using a calibrated photodiode to measure the current and calculate irradiance using the formula E = I/(R*Ad), where R is the responsivity and Ad is the detector area. The discussion emphasizes the importance of understanding terms like irradiance and radiance, as they can be confusing in the context of LED measurements. Additionally, it highlights the need for specific parameters such as the emitting area and angular beam width for accurate calculations.

PREREQUISITES
  • Understanding of LED specifications and parameters
  • Knowledge of photodiodes and their responsivity
  • Familiarity with basic optics concepts, including irradiance and radiance
  • Ability to perform arithmetic calculations involving power and area
NEXT STEPS
  • Research how to use a calibrated photodiode for measuring LED output
  • Learn about calculating irradiance and radiance in optical systems
  • Explore the significance of angular beam width (FWHM) in LED applications
  • Investigate the datasheets of various LEDs for detailed specifications
USEFUL FOR

Researchers and engineers working with LEDs in applications such as photocatalysis, optical engineers, and anyone involved in measuring light intensity and irradiance from LED sources.

rc101268
Messages
5
Reaction score
0
I have LEDs of 0.7mW, but for my experiments, I want my values to be in light intensity unit - W/cm2.
I cannot figure out how to do the conversion.
 
Science news on Phys.org
Light intensity of your (not quite point-like) source, or light intensity at some object lit by your source?

In both cases it is just a simple arithmetics (under assumption your LED emits uniformly in all directions)
 
rc101268 said:
I have LEDs of 0.7mW, but for my experiments, I want my values to be in light intensity unit - W/cm2.
I cannot figure out how to do the conversion.
The best way to do this is to measure physical quantities in order to calculate the irradiance (IMO, a more appropriate and less confusing term than intensity*) in (watts/cm^2). Here's the procedure.

1. Get a photo diode with calibrated responsivity (R, in amps/watt) at the wavelength of the LED and known detector area, Ad.
2. Place the detector a known distance, z, away from the LED.
3. Measure the current, I, passing through the LED. You may have to turn the room lights out. Or measure the current with LED on and then again with the LED off then take the difference.
4. The LED irradiance at the detector, and in that direction, is
E = I/(R*Ad)
5. A more useful property of the LED is its radiance, an optical invariant. If you know the emitting area, As, of the LED, Then its radiance is
L = I*z^2/(R*Ad*As*cos(theta)).

where theta the angle of the line of sight from the normal of the LED to the normal of the detector.

All this assumes that the size of the LED and detector are small compared to the distance, z.

* Intensity is a confusing term because different authors have different meanings for the term. Some authors use it to mean irradiance (power received/receiving area, in watts/cm^2) but some authors use it to mean "intensity" (power emitted/solid angle, in watts/steradian).
 
Last edited:
The LEDs are being used to experiment with photocatalysis.

@xts
It's the light intensity of the source (LEDs)

@aabottom
I was hoping I won't have to go down that road as I don't have a calibrated photodiode.
I think from your asterisked comment, what I am looking for is irradiance but its more like power emitted/receiving area (W/cm^2).
Wish there was a simple formula
 
rc101268 said:
The LEDs are being used to experiment with photocatalysis.

@xts
It's the light intensity of the source (LEDs)

@aabottom
I was hoping I won't have to go down that road as I don't have a calibrated photodiode.
I think from your asterisked comment, what I am looking for is irradiance but its more like power emitted/receiving area (W/cm^2).
Wish there was a simple formula
It is a simple formula (e.g. 4 or 5 in my post above). You just don't have the information you need to make the calculation.

Is 0.7 mW the total power emitted by the LED?
Do you know the emitting area of the LED?
Do you have graphs showing the angular beam width of the LED or the angular beam width (Full Width Half Maximum- FWHM)?

If the emitting area, As, and the angular beam width (FWHM), b, are small, the average radiance normal to the LED surface is
L = P/(2*As*b^2)
where P is the total power emitted by the LED.

With the LED radiance, you can estimate the irradiance at any distance, z, (in the far field) from the LED.
E = L*As*/z^2

PS: The power emitted/receiving area (W/cm^2) is likley not very useful. If you need to know the Radiant Exitance, M, then calculate
M = P/As
 
Last edited:
I'll just find the datasheet of the LED, hopefully all that information should be there.
Thanks aabottom.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 10 ·
Replies
10
Views
8K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
12K
  • · Replies 40 ·
2
Replies
40
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K