Determining static equilibrium this way?

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Discussion Overview

The discussion revolves around the conditions for static equilibrium of a rigid beam supported by vertical rods. Participants explore whether calculating moments about multiple points can determine equilibrium in both two-dimensional and three-dimensional statically determinate systems.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant describes a method for calculating reactions at supports by taking moments about points A and B, questioning if this method is generally applicable.
  • Another participant agrees that moments must be zero for equilibrium but notes that with more than two points, additional information about the system's flexibility is required to determine reactions.
  • A third participant clarifies that they are specifically referring to statically determinate systems and seeks confirmation on the validity of using moments without summing external forces.
  • A later reply asserts that taking moments about each support, along with an equation for vertical forces, will solve the problem if the system is statically determinate and has a limited number of supports.

Areas of Agreement / Disagreement

Participants generally agree that moments must be zero for equilibrium, but there is disagreement regarding the applicability of the method when more than two supports are involved and the necessity of additional information about the system's flexibility.

Contextual Notes

The discussion is limited to statically determinate systems and does not address cases where systems may be indeterminate or flexible.

Termotanque
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Suppose that one has a heavy rigid beam supported by two vertical rods at two different points A and B, and wants to calculate the reaction R_A, R_B made by the rods.

I found the reactions first by taking moments with respect to A, and then with respect to B. In both cases I included the moment of the weight. The solutions were correct.

I want to know if this is just a particular case, or if in general it is true that if the sum of the moments with respect to n (possibly 2) different points A, B, ... are all null, then the rigid body is at equilibrium.

Sorry for not using pretty Tex, but it's not rendering properly.
 
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HI Termotanque! :smile:

(try using the X2 icon just above the Reply box :wink:)
Termotanque said:
I want to know if this is just a particular case, or if in general it is true that if the sum of the moments with respect to n (possibly 2) different points A, B, ... are all null, then the rigid body is at equilibrium.

Yes and no. :biggrin:

Yes, all the moments have to be zero for there to be equilibrium, but if there's more than 2 points (for a rod) or more than 3 points (for a plate), then no, there's insufficient information to find the reactions, and you need to know something about the flexibility of the rod or plate also.

For example, with an ordinary four-legged table, you can remove any leg and the table will still stand … if you know nothing about the flexibility of the table, you can't tell how much weight is being supported on each of the four legs. :wink:
 
I'm actually only referring to statically determinate systems. One which one could find the reactions (like the one I described above). I wasn't asking if it's possible to find the reactions, but if it's correct to do it just by calculating a finite number of moments with respect to interesting points, and not calculating the sum of external forces.

Even though my example was 2 dimensional, I want to know the answer for a more general 3 dimensional statically determinate system.
 
(just got up :zzz: …)

Yes, taking moments about each point of support (plus one equation for the vertical components of force) will always solve the problem if the number of supports is small enough to be statically determinate. :smile:
 

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