Determining the focal length of a compound lens

AI Thread Summary
The discussion centers on calculating the focal length of a compound lens system made up of two biconvex lenses, L_1 and L_2, with focal lengths of 15 cm and 25 cm, respectively. The formula used for the calculation is 1/f_c = 1/f_1 + 1/f_2. Initially, there was confusion regarding whether to use absolute values for the focal lengths, but it was clarified that both focal lengths are positive for biconvex lenses. The correct focal length of the compound lens is determined to be +9.375 cm, confirming that absolute values were not necessary in this case. This resolution highlights the importance of understanding the sign conventions for lens focal lengths.
Alex_Neof
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Homework Statement


A biconvex lens, L_1, with focal length of magnitude \left|<br /> f_1 <br /> \right|<br /> = 15 cm is used with a second biconvex lens, L_2, with focal length of magnitude \left|<br /> f_2 <br /> \right|<br /> = 25 cm to form a compound lens system.

If the two lenses are placed in mutual contact what is the focal length of the compound lens?

Homework Equations



\frac{1}{f_c} = \frac{1}{f_1} + \frac{1}{f_2}

The Attempt at a Solution


It's just a matter of plugging into the above equation.. However do I use the the absolute values or the fact that for a biconvex lens

<br /> f_1 &gt; 0

and

<br /> f_2 &lt; 0?

Solution given is +9.375 cm, which suggests you use the absolute values, however I am not fully convinced as it was not specified in the course notes whether to use absolute values or not.

Not using absolute values, I find the focal length to be +37.5 cm
 
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Sorry, I figured it out... both are biconvex lenses therefore their focal lengths are positive. I believe I got confused with radius' of curvatures.. the solution given is the correct one.
 
For a biconvex lens:

R1 > 0 and R2 < 0 (Radius of curvature)

not the focal lengths... :confused:
 
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