I have been asked to determine the pdf given a DF.(adsbygoogle = window.adsbygoogle || []).push({});

F(x) = 0 for x<0

F(x) = x^2/x for x 0<= x < 1

F(X) = x/2 for 1<=x<2

F(x) = 1 for x>= 2

Is the pdf the derivative of the df

So if you wanted the probability of x between 0 and 1

The pdf would just be x ?

regards

Brendan

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# Df to pdf

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