Diagonal, Jordan Normal and And Inverses

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1) Is a diagonal matrix always invertable?
2) Is an Invertable matrix always Diagonalizable?
3) Is a matrix in jordan normal form always invertable

The answers are prob straight foward but I am confused.
 
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Jordan Normal, Diagonal and Inverses

Homework Statement



1) Is a diagonal matrix always invertable?
2) Is an Invertable matrix always Diagonalizable?
3) Is a matrix in jordan normal form always invertable

The answers are prob straight foward but I am confused.

Homework Equations





The Attempt at a Solution

 
I've had a thought about this, I guess what I am looking for is some sort of relation between the characteristic polinomial and the determinant of a the matrix.
 
1) No. Let d_{i} be the diagonal entries of a diagonal matrix The inverse (if it exists) consists of the values \frac {1}{d_{i}} along the diagonal. Therefore, all d_{i}'s must be nonzero for the inverse to exist.

2) No. If an nxn matrix is diagonalizable, it must have n linearly independent eigenvectors. A = \left(\begin{array}{cc}1&0\\1&1\end{array}\right) is invertibile but not diagonalizable.

3) I don't know. :rolleyes:
 


Is
\begin{bmatrix}1 & 0 & 0 \\ 0 & 1 & 0\\ 0 & 0 & 0\end{bmatrix}
invertible?
 
Thanks greatly.

That clears it all up.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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