Diagonalizing a metric by a coordinate transformation

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The discussion centers on diagonalizing the metric ds² = -dt² + dx² + 2a²(t)dxdy + dz². The lecturer indicated that the submitted solution is a specific case rather than a general solution, emphasizing the need for the function F to depend on all relevant parameters. To achieve a general solution, the function F must accommodate variations in parameters like 'a'. The participant expresses confusion in translating this requirement into their solution. Seeking examples of similar problems may aid in understanding how to derive the general solution effectively.
Lilian Sa
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Homework Statement
gravity
Relevant Equations
metric transformation
hey there :)

So I had a homework, and I was asked to diagonalize the metric ##{ds}^2=-{dt}^2+{dx}^2+2a^2(t)dxdy+{dz}^2## and to find the coordinate transformation for the coordinates of the new metric.
so I found the coordinate transformation but the lecturer said that what I found is a specific solution and not the general solution.
And he said that the function F (I attached my solution) is a function that should be dependent on the other parameter of the problem.
and I don't know how to translate this.
I started to solve it from the start but I got entangled >_<

thank you :)
 

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It sounds like your lecturer wants you to find a more general solution. To do this, you need to find a function F that is dependent on all of the parameters in the problem. For example, if you have a parameter a, then your function F should depend on a as well. In addition, your solution should work for any value of a (not just a specific one). If you are struggling to find the general solution, it might be helpful to look up some examples of how to solve similar problems. This could give you an idea of what the general solution should look like.
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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