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Diagram for the Structure of BrCl4+?

  1. Nov 26, 2008 #1
    1. The problem statement, all variables and given/known data
    Draw a diagram for the structure of BrCl4+. This should be a VSEPR diagram.


    2. Relevant equations
    N/A.


    3. The attempt at a solution
    Br has 7 valence electrons.
    Cl has 7 valence electrons.
    7(5)=35, but we take away one electron because of the +1 positive charge. Now I have 34 electrons to deal with.

    Put Br as the central atom.

    Bond 4 Cl to it.

    Complete the octet of Cl. This uses up 32 electrons total.

    You have two electrons left over: put them as a pair on the Br.

    This gives four bonding domains, and one nonbonding domain, so I drew a distorted tetrahedral shape.

    But... apparently this is wrong, because the program won't accept that as an answer. Any ideas where my error was?
     
  2. jcsd
  3. Jan 19, 2017 #2

    TeethWhitener

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    Science Advisor
    Gold Member

    You've done everything right, and you have 4 atoms + 1 lone pair around a central atom. In the US, we typically refer to the resulting shape as a "see-saw" shaped molecule. It's close to a tetrahedron, but the axial atoms are typically 180° from each other.
     
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