Diagram for the Structure of BrCl4+?

In summary, the task was to draw a VSEPR diagram for the structure of BrCl4+. The solution involved placing Br as the central atom and bonding 4 Cl atoms to it, completing the octet of Cl and leaving 2 electrons as a lone pair on Br. The resulting shape is a distorted tetrahedron, also known as a "see-saw" shape.
  • #1
jumbogala
423
4

Homework Statement


Draw a diagram for the structure of BrCl4+. This should be a VSEPR diagram.

Homework Equations


N/A.

The Attempt at a Solution


Br has 7 valence electrons.
Cl has 7 valence electrons.
7(5)=35, but we take away one electron because of the +1 positive charge. Now I have 34 electrons to deal with.

Put Br as the central atom.

Bond 4 Cl to it.

Complete the octet of Cl. This uses up 32 electrons total.

You have two electrons left over: put them as a pair on the Br.

This gives four bonding domains, and one nonbonding domain, so I drew a distorted tetrahedral shape.

But... apparently this is wrong, because the program won't accept that as an answer. Any ideas where my error was?
 
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  • #2
You've done everything right, and you have 4 atoms + 1 lone pair around a central atom. In the US, we typically refer to the resulting shape as a "see-saw" shaped molecule. It's close to a tetrahedron, but the axial atoms are typically 180° from each other.
 

What is the chemical formula for BrCl4+?

The chemical formula for BrCl4+ is BrCl4+.

What is the structure of BrCl4+?

The structure of BrCl4+ consists of a central bromine atom bonded to four chlorine atoms in a tetrahedral shape. The positive charge is located on the central bromine atom.

What is the molecular geometry of BrCl4+?

The molecular geometry of BrCl4+ is tetrahedral.

What is the hybridization of BrCl4+?

The hybridization of BrCl4+ is sp3, since the central bromine atom is bonded to four atoms and has no lone pairs.

What are the properties of BrCl4+?

BrCl4+ is a polar molecule with a melting point of -40.5°C and a boiling point of 92.9°C. It is also highly reactive and can act as a strong oxidizing agent.

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