# Diagram for the Structure of BrCl4+?

1. Nov 26, 2008

### jumbogala

1. The problem statement, all variables and given/known data
Draw a diagram for the structure of BrCl4+. This should be a VSEPR diagram.

2. Relevant equations
N/A.

3. The attempt at a solution
Br has 7 valence electrons.
Cl has 7 valence electrons.
7(5)=35, but we take away one electron because of the +1 positive charge. Now I have 34 electrons to deal with.

Put Br as the central atom.

Bond 4 Cl to it.

Complete the octet of Cl. This uses up 32 electrons total.

You have two electrons left over: put them as a pair on the Br.

This gives four bonding domains, and one nonbonding domain, so I drew a distorted tetrahedral shape.

But... apparently this is wrong, because the program won't accept that as an answer. Any ideas where my error was?

2. Jan 19, 2017

### TeethWhitener

You've done everything right, and you have 4 atoms + 1 lone pair around a central atom. In the US, we typically refer to the resulting shape as a "see-saw" shaped molecule. It's close to a tetrahedron, but the axial atoms are typically 180° from each other.