What does this tell you about the voltage across the first capacitor?PhanicKnight said:
What does this tell you about the ratio of two capacitances?PhanicKnight said:
Why? What can you say about the E-field between C and D?PhanicKnight said:
Okay, so φd actually is 0. I tried something (see picture underneath), but I'm not sure if it's correct as I don't have correct answers.cnh1995 said:
A plate capacitor is a device used to store electrical energy by creating an electric field between two conducting plates separated by a dielectric material. It is commonly used in electronic circuits and can store large amounts of charge.
The electric potential difference, also known as voltage, is represented by the distance between the two plates in a plate capacitor diagram. The larger the distance between the plates, the higher the voltage and vice versa.
The electric potential difference in a plate capacitor is affected by the distance between the plates, the magnitude of charge on the plates, and the dielectric constant of the material between the plates. It is also influenced by the external voltage applied to the capacitor.
The electric potential difference in a plate capacitor can be calculated by dividing the charge on one plate by the capacitance of the capacitor. It can also be calculated by multiplying the electric field between the plates by the distance between the plates.
The electric potential difference in a plate capacitor determines the amount of energy that can be stored in the capacitor. It is also used to calculate the electric field strength and the amount of work required to move a charge between the plates of the capacitor.