Diagramming the Integral: A Visual Guide

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Homework Help Overview

The problem involves drawing a diagram to represent the area over which a given integral is integrated, specifically the integral of the function 2x² + y with specified boundary conditions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to create a diagram based on their understanding of the integral and its limits but expresses uncertainty about its accuracy. Other participants question the clarity of the provided diagram and suggest improvements based on the integral's boundaries.

Discussion Status

Participants are actively engaging with the original poster's diagram, providing feedback and suggesting corrections. There is a focus on refining the understanding of the area represented by the integral, with some guidance offered regarding the correct boundaries and shape of the region.

Contextual Notes

There are indications of missing attachments and the need for clearer definitions of the integral and area, which may affect the discussion's progress.

mmh37
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Problem:

"Draw a Diagram to show over which area the following integral (see integral in attached file) is integrated."

I drew a little diagram of what I think the area looks like (see diagram). But I am very, very insecure about what I did and would appreciate if anyone could have a look at it and let me know if I did something wrong. That would be really helpful!
 

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  • diagram.jpg
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I can't see the attachments yet, perhaps you could give the integral and the area? Try LaTeX :wink:
 
[tex]\int {2x^2+y} dxdy[/tex]

and the boundary conditions are

for x: y < x < 2-y

for y: 0 < y < 1

hope that helps
 
The outer integral is y so first draw to horizontal lines at y= 0 and y= 1 to define the limits for y. Now, for each y, x lies between y= x and x= 2- y which is the same as y= 2- x. However, in your picture you have x running between 0 and x. Move your stripes (indicating the figure) to the triangle formed by y= x, y= 2- x, and y= 0. (0f course, you notice that y= 2- x and y= x cross at y= 1.)
 
thanks for this!

I'm not sure whether this second attempt is right, but here is the new diagram anyway (with inverted strips):
 

Attachments

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