Did I do my loop analysis correctly?

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Discussion Overview

The discussion revolves around the correctness of loop analysis in a circuit problem, specifically focusing on the calculated loop currents and their implications for the overall current output.

Discussion Character

  • Homework-related, Technical explanation, Debate/contested

Main Points Raised

  • One participant presents initial loop current values: I1 = 1mA, I2 = 6mA, I3 = 2mA, leading to a calculated I0 of -1mA.
  • Another participant asserts that the initial answer is incorrect, suggesting that checking the work reveals inconsistencies with the voltage across the 20V source.
  • A later reply provides revised loop current values: I1 = 3mA, I2 = -1mA, I3 = -1mA, resulting in a new I0 of 4mA.
  • There is an implication that the method of checking the work is straightforward, but the correctness of the revised values remains unverified by others.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correctness of the initial or revised loop current calculations, indicating ongoing disagreement regarding the analysis.

Contextual Notes

There are unresolved aspects regarding the assumptions made in the loop analysis and the specific conditions under which the calculations were performed.

naivy
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Homework Statement



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Homework Equations





The Attempt at a Solution



If we were to call the bottom right loop I1, the top loop I2, and the bottom right loop I3. I got the following:

I1 = 1mA
I2 = 6mA
I3 = 2mA

Which gives me a final answer of I0 = -1mA.

Is this correct?
 
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No, it is not correct.
 
checking your answer is trivial. All the loop currents become immediately obvious once you assume you have I0, and then you can get the voltages across the resistors and when you add them up, you'll find that the voltage across the 20V source is not 20V, so clearly you have the wrong answer. Learn how to check you work. It's often just this simple.
 
I fixed it and got:

I1 = 3mA
I2 = -1mA
I3 = -1mA

Which gives me a final answer of I0 = 4mA.
 

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