Did You Ace the Calculus Calculation Contest as a Sophomore?

AI Thread Summary
Participants discuss their experiences and techniques related to a calculus contest, highlighting the use of binomial coefficients and Leibniz's rule for derivatives. There is skepticism about the practicality of calculating higher-order derivatives, with many agreeing that only the second or third derivatives are typically necessary for most applications. The conversation touches on the value of learning mathematical tricks, with references to educational resources like Mary Boas' book. Some express frustration with the perceived redundancy of certain calculus topics, questioning their relevance in a broader educational context. The discussion reflects a blend of personal anecdotes and mathematical insights, emphasizing the balance between theoretical knowledge and practical application in calculus.

Time yourself on this! What's the 4th derivative of x²sin(2x²)?

  • Less then 10 seconds.

    Votes: 2 13.3%
  • 10~60 seconds.

    Votes: 4 26.7%
  • More then 60 seconds.

    Votes: 6 40.0%
  • I rather stick with IMO math olympiad questions.

    Votes: 3 20.0%

  • Total voters
    15
JWHooper
I'll work on it, and I'll show my time.
 
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65 seconds.
 
Is there a "I think it's a waste of time" option?
 
is there a book somewhere of all these cute little tricks like the generalized product rule? and don't go telling me that i should be able to figure em out on my own.
 
I don't know about an entire book devoted only to tricks, but I first learned that one from Mary Boas' Mathematical Methods for the Physical Sciences. I think you will find physicists use these kinds of tricks most often; it has become common in the math department to say "here are the basic rules, specific examples are a waste of time."

Is there a "I think it's a waste of time" option?

Be careful, teaching introductory calculus is the main source of employment for math PhDs (from the perspective of university administration). Calling any part of math "a waste of time" is a slippery slope, since it quickly becomes hard to justify any of it as time well spent.
 
Finding the fourth derivative of some product is really quite pointless though no? The vast majority of geometrical and physical applications require only up to the 2nd or 3rd derivative at most.

PS. It takes me 20 seconds if you let me leave the answer in series form. Don't ask me why I did it.

EDIT: ice109, here's one: https://www.physicsforums.com/showthread.php?t=206039
 
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Gib Z said:
Finding the fourth derivative of some product is really quite pointless though no? The vast majority of geometrical and physical applications require only up to the 2nd or 3rd derivative at most.

PS. It takes me 20 seconds if you let me leave the answer in series form. Don't ask me why I did it.

EDIT: ice109, here's one: https://www.physicsforums.com/showthread.php?t=206039

do you read the posts in the threads you post in? did you not see the link to the leibniz identity like 3 posts back?
 
Does anyone dare give their answer?
 
  • #10
ice109 said:
do you read the posts in the threads you post in? did you not see the link to the leibniz identity like 3 posts back?

Do you read the links posted? That identity is in terms of lower derivatives, but derivatives still. What i meant was the write the sine term in its series form, multiply through by the x term and finding the 4th derivative of the resulting series.
 
  • #11
Gib Z said:
Finding the fourth derivative of some product is really quite pointless though no? The vast majority of geometrical and physical applications require only up to the 2nd or 3rd derivative at most.

PS. It takes me 20 seconds if you let me leave the answer in series form. Don't ask me why I did it.

The irony is that the direct way to calculate coefficients of a power series is by evaluating higher order derivatives! Of course this is almost never done in practice since we keep working with the same 10 functions who p-series we know by heart, but Liebniz's formula is very helpful once we venture out of the familiar functions, e.g.

Prove:

\sqrt{\frac{\pi }{2 x}} J_{\frac{1}{2} (2<br /> n+1)}(x)=x^n \left(-\frac{x^{-1} d}{ dx}\right)^n \frac{\sin<br /> (x)}{x}

where the bessel function J_p(x) is given by:

J_p(x)=\sum _{n=0}^{\infty } \frac{(-1)^n<br /> \left(\frac{x}{2}\right)^{2 n+p}}{\Gamma (n+1) \Gamma (n+p+1)}

If I remember correctly I spent ~2 hours working on this problem as a sophomore, and along the way I used a lot of tricks; Liebniz's rule was essential, and the most difficult part was getting the factorial terms to match up.
 
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  • #12
As a sophomore? Man, you must have gone to a better school than I did.
 
  • #13
daveyinaz said:
As a sophomore? Man, you must have gone to a better school than I did.

Not really, I went to a fourth tier state school in my home town. Fortunately I had a good physics professor, and there was another good student at that time as well. That problem was given to us as part of a take-home test in the math methods course that used the Boas book I mentioned earlier. Most classmates showed that the first few terms of the two series were equal, and that received full credit! What a strange education I've had...
 
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