Diff eq, need a simple step explained

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This discussion focuses on solving a homogeneous differential equation (DE) using substitution methods. The specific transformation involves setting \( y = ux \) and simplifying the equation from \((x^{2}+u^{2}x^{2})dx+\left(x^{2} - ux^{2}\right)\left[udx + xdu\right]=0\) to \(x^{2}(1 + u)dx + x^{3}(1-u)du=0\). Key steps include expanding and simplifying the expressions to achieve the final form. The discussion highlights the importance of recognizing substitution techniques in solving differential equations.

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frozenguy
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So its not a problem, but a step in an example that I need explained. The section is solutions by substitutions and its an example of solving a homogeneous DE.

Step goes from:
[tex]\left(x^{2}+u^{2}x^{2}\right)dx+\left(x^{2} - ux^{2}\right)\left[udx + xdu\right]=0[/tex]

to:
[tex]x^{2}\left(1 + u\right)dx + x^{3}\left(1-u\right)du=0[/tex]

It had previously set y=ux, a few steps back.
 
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frozenguy said:
So its not a problem, but a step in an example that I need explained. The section is solutions by substitutions and its an example of solving a homogeneous DE.

Step goes from:
[tex]\left(x^{2}+u^{2}x^{2}\right)dx+\left(x^{2} - ux^{2}\right)\left[udx + xdu\right]=0[/tex]
Just expand the expressions above, and simplify.
[tex](x^2 + u^2x^2 + x^2u - u^2x^2)dx + (x^3 - ux^3)du = 0[/tex]
frozenguy said:
to:
[tex]x^{2}\left(1 + u\right)dx + x^{3}\left(1-u\right)du=0[/tex]

It had previously set y=ux, a few steps back.
 
Thank you... I don't know why I didn't see this before.. Ok I feel stupid. :/
 

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