- #1
Warr
- 120
- 0
I took an ODE course last year, but I seem to have forgotten some stuff. I need to solve this equation:
[tex]\frac{d^2u}{dt^2} + {\omega}^2u = f_osin({\mu}t)[/tex]
with the boundry conditions:
u(0) = 0, du/dt(0) = 0
When I tried to solve the homogenenous equation first, I got
[tex]u_g(t)=c_1e^{i{\omega}t}+c_2e^{-i{\omega}t}[/tex]
I then differentiated and set up the system with the two boundy conditions...but I got c1+c2=0 and c1-c2=0...c1=c2=0.
This seems wrong. Any help would be appreciated
[tex]\frac{d^2u}{dt^2} + {\omega}^2u = f_osin({\mu}t)[/tex]
with the boundry conditions:
u(0) = 0, du/dt(0) = 0
When I tried to solve the homogenenous equation first, I got
[tex]u_g(t)=c_1e^{i{\omega}t}+c_2e^{-i{\omega}t}[/tex]
I then differentiated and set up the system with the two boundy conditions...but I got c1+c2=0 and c1-c2=0...c1=c2=0.
This seems wrong. Any help would be appreciated