Difference between color / temperature?

Click For Summary
The discussion centers on the differences between red objects at room temperature and heated red objects, particularly metals. Both types appear red due to specific wavelengths of light being reflected or emitted, but their thermal properties differ significantly. Heated metals emit a broad spectrum of electromagnetic radiation, primarily in the infrared range, which is not present in cooler red objects like flowers. While our eyes may not distinguish between the two based solely on color, infrared detection can reveal temperature differences. The conversation also touches on the complexities of spectral analysis and the challenges of accurately measuring color perception.
revv
Messages
55
Reaction score
9
What is the difference between a red object at room temperature and a heated red object (Metal for example).

They are both red except one is cooler then the other?

Why aren't the red objects in my room not hot like the heating of a metal?
 
Science news on Phys.org
Red means some electromagnetic waves of a certain wavelength fall into your eyes. It does not allow to conclude, where those waves were created from. In case of a hot metal the source is the electrons of the heated metal atoms. In case of a red flower, it is the daylight minus all wavelengths which the flower absorbs, i.e. only red isn't absorbed but reflected. Now daylight comes from the sun, which is hot, too, only farther away. However, I suppose the creation process is a different one.
 
  • Like
Likes Klystron, davenn, pinball1970 and 1 other person
revv said:
What is the difference between a red object at room temperature and a heated red object (Metal for example).
The spectra are different. For a hot 'black body' the spectrum covers the whole of the EM spectrum with a peak around the 'red' wavelengths and, for a pigment, the spectrum of reflected (white) light will be a band of wavelengths around the red wavelengths (depending on the quality of the pigment.
Our eyes are very poor spectrometers and, under the right viewing conditions, those two 'red' colours could be completely indistinguishable. We could possibly distinguish between two test objects by the fact that we could feel the IR wavelengths against our face and conclude the hot object is in fact hot but the cold red object is not. But the eyes would probably not help in deciding which is which.
If the EM from a red hot object were passed through a good red filter, the spectrum would be pretty much the same as when white light is passed through the filter because the black body spectrum is broad and doesn't change much over any chosen narrow band section.
 
sophiecentaur said:
For a hot 'black body' the spectrum covers the whole of the EM spectrum with a peak around the 'red' wavelengths
I proved to myself a couple of years ago that there is green light present in a red/orange hot electric stove burner. (≈1500°F / 800°C)

2016.12.03.red.hot.things.are.also.green.png

This image was taken through diffraction grating.

I also captured the fuzzy spectrum of the neon "On" lamp on the front of my stove, which is a different kind of "color" altogether. (I think. :biggrin:)
 

Attachments

  • 2016.12.03.red.hot.things.are.also.green.png
    2016.12.03.red.hot.things.are.also.green.png
    53.4 KB · Views: 633
  • Like
Likes sophiecentaur and russ_watters
revv said:
What is the difference between a red object at room temperature and a heated red object (Metal for example).

They are both red except one is cooler then the other?

Why aren't the red objects in my room not hot like the heating of a metal?
Oh my.
For several years I've been wanting to do a "spectral analysis" of a banana, to figure out if it's true that they aren't really yellow.
Your question finally prompted me to do the experiment.
Albeit, I used a lemon this morning, as, I kept eating my previous experimental subjects...

Anyways, here are the results of this morning's experiment:

Experimental apparatus:
2018.08.07.spectrometry.device.png



Subject of experiment:
2018.08.07.lemon.in.spectrometry.device.png


Results of experiment:
2018.08.07.spectral.analysis.of.a.lemon.png


Conclusion: Lemons are white? :oldconfused:

hmmmm...
 

Attachments

  • 2018.08.07.spectrometry.device.png
    2018.08.07.spectrometry.device.png
    102.4 KB · Views: 593
  • 2018.08.07.lemon.in.spectrometry.device.png
    2018.08.07.lemon.in.spectrometry.device.png
    67 KB · Views: 675
  • 2018.08.07.spectral.analysis.of.a.lemon.png
    2018.08.07.spectral.analysis.of.a.lemon.png
    57.8 KB · Views: 580
  • Like
Likes Andy Resnick
OmCheeto said:
Conclusion: Lemons are white?
Conclusion: Eyeballing intensity levels at different frequencies and is not a good way to quantitatively measure a spectrum. The logarithmic response of the eyes will tend to make every frequency appear to be illuminated with rough uniformity.

Conclusion: Every experiment needs a control. If you look at the spectrum for an apple, or a piece of white paper compare it to one for a lemon and fail to find a difference then you have a real problem with your methodology. If you do find a difference, now you're getting a meaningful result. Side by side recommended -- eyes are designed to detect differences in illumination, edges.
 
  • Like
Likes OmCheeto
OmCheeto said:
Conclusion: Lemons are white?
Run the eye dropper sample tool on your Photo processing program and notice the RGB values on the image. There may be a Luminance option button - or convert to monochrome. That will show you a difference when compared to a white card (in shadow to avoid 255 255 255 saturation)
 
  • Like
Likes OmCheeto

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K