1. The problem statement, all variables and given/known data The phase of -7cos(5x-3) is -3/5 The phase of -cot(3x-4) is 4/3 2. Relevant equations 3. The attempt at a solution Why the difference in the signs of phases? I think the phase of -cot(3x-4) should be -4/3. Its an odd function: -cot(3x-4)=cot(-3x+4) and even then its phase looks to be -4/3. Also, would -7cos(5x-3) equal -7cos(-5x+3) because it's an even function? Thanks.