- #1
Numnum
- 19
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If I were to calculate the probability of getting 6 out of 6 numbers correct in a lottery where you choose six numbers out of 49 (the lottery is called 6/49), the probability would be
(6C6)(43C0)/(49C6), right? But what are different methods of getting this same answer without using combinations?
(6C6)(43C0)/(49C6), right? But what are different methods of getting this same answer without using combinations?