Differential Amplifier: Neglecting ro, why?

AI Thread Summary
In a differential amplifier, the output resistance (ro) is often neglected in calculations because the resistive load (Rc) is typically much smaller than ro. When analyzing the emitter junction, the effective load is primarily determined by Rc, as the parallel combination of Rc and ro results in an impedance that closely resembles Rc. This simplification is valid when ro is significantly greater than Rc, making the impact of ro negligible. To confirm this assumption, one should compare the values of Rc and ro to see which is greater and the extent of the difference. Understanding this relationship is crucial for accurate analysis of differential amplifier performance.
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Homework Statement



Pretty straightforward. Attached is a small signal picture of a differential amplifier. Summing currents at the emitter junction, the text says: "Because the transistors have resistive loads, the output resistance will be neglected in the calculations."

Why is this?

Homework Equations





The Attempt at a Solution

 

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The true load on one side of the diff amp is Rc in parallel with ro. Often instead of resistor loads (Rc), current sources are used. The equivalent impedance of a current source will be comparable to ro and then the parallel combination will be an impedance much different from the impedance of the current source.

In this case, the value of Rc is probably much less than ro, and the parallel combination of the two will have an impedance not much different than Rc. In other words, ro is so much greater than Rc that including it doesn't change the effective load; the effective load is just Rc.

Check the value of Rc and ro and see which is greater, and how much greater.
 
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