- #1
RedBarchetta
- 50
- 1
Any help is greatly appreciated!
1.Differentiate.
http://www.webassign.net/www16/symImages/8/a/e5af282af9dd30006849e16c0b489b.gif
2.Find the derivative of the function.
http://www.webassign.net/www16/symImages/c/8/fd38a158e810bff80a28202fbceb37.gif
3.Consider the following.
http://www.webassign.net/www16/symImages/8/a/68e64f2907886f5478f5c03714da01.gif
(a) Find y ' by implicit differentiation.
(b) Solve the equation explicitly for y and differentiate to get y ' in terms of x.
4.Differentiate.
http://www.webassign.net/www16/symImages/1/a/d96706921943b5f83c856dd9fda12e.gif
5.Differentiate
http://www.webassign.net/www16/symImages/d/d/cc0e49fd81af528239a0b21a0ac5e9.gif
1.On this one I started with the Quotient Rule.
y=sinx/1+cosx
y'=cosx(1+cosx)+(sinx)^2/(1+cosx)^2
y'=cosx+(cosx)^2+(sinx)^2/(1+cosx)^2
I type this in:
(cos(x)+cos^2(x)+sin^2(x))/(1+cos^2(x))
It says: "Check the syntax of your response." I've tried putting them like(cos(x))^2 and (cos^2(x)).
2.I tried this one with the chain rule.
I converted it:
s(t)=(t^3+3/t^3-3)^1/4
Now the derivative of the inside is what gets me.
s'(t)=1/4(t^3+3/t^3-3)^-3/4*(inside)
The inside derivative ends up equaling zero. I'm stumped. I used the quotient rule. Heres my attempt of the inside derivative=
3t^2(t^3-3)-(t^3+3)3t^2/(t^3-3)^2
The numerator equals zero, so that times the first part is zero, leaving me with zero. I tried zero but it was wrong.
3.Alright, differentiate with respect to x right? I started by converting the radicals.
x^1/2+y^1/2=6
Derivative:
1/2x^(-1/2)+1/2y^(-1/2)y'=6
6 is a constant and equals zero, so I moved the x term over, then divided by 1/2y to get y' by it self:
(-.5x^(.5))/(.5y^(-.5))
Wrong. I didnt attempt the second part yet.
4. The derivative(so I've read) of e^x, is simply e^x. I converted the radical. Then applied the product rule.
1/2x^(-1/2)*e^x+x^(1/2)*e^x
Wrong. I think I might have not applied the chain rule to the last term. so If you take the derivative of e^x, it should be e^x? But that shouldn't matter because its still e^x. Right?
5. I took the 2nd power and applied to the the entire term.
(1-u/1+u)^2
Then used chain rule.
2(1-u/1+u)*(inside derivative)
inside=
-1(1+u)-(1-u)*1/(1+u)^2
-1-u-1+u/(1+u)^2
-2/(1+u)^2
final answer:
2(1-u/1+u)*(-2/(1+u)^2)
Still wrong. I'm not sure. This is what I typed: 2((1-u)/(1+u))*(-2)/(1+u)^2
Homework Statement
1.Differentiate.
http://www.webassign.net/www16/symImages/8/a/e5af282af9dd30006849e16c0b489b.gif
2.Find the derivative of the function.
http://www.webassign.net/www16/symImages/c/8/fd38a158e810bff80a28202fbceb37.gif
3.Consider the following.
http://www.webassign.net/www16/symImages/8/a/68e64f2907886f5478f5c03714da01.gif
(a) Find y ' by implicit differentiation.
(b) Solve the equation explicitly for y and differentiate to get y ' in terms of x.
4.Differentiate.
http://www.webassign.net/www16/symImages/1/a/d96706921943b5f83c856dd9fda12e.gif
5.Differentiate
http://www.webassign.net/www16/symImages/d/d/cc0e49fd81af528239a0b21a0ac5e9.gif
The Attempt at a Solution
1.On this one I started with the Quotient Rule.
y=sinx/1+cosx
y'=cosx(1+cosx)+(sinx)^2/(1+cosx)^2
y'=cosx+(cosx)^2+(sinx)^2/(1+cosx)^2
I type this in:
(cos(x)+cos^2(x)+sin^2(x))/(1+cos^2(x))
It says: "Check the syntax of your response." I've tried putting them like(cos(x))^2 and (cos^2(x)).
2.I tried this one with the chain rule.
I converted it:
s(t)=(t^3+3/t^3-3)^1/4
Now the derivative of the inside is what gets me.
s'(t)=1/4(t^3+3/t^3-3)^-3/4*(inside)
The inside derivative ends up equaling zero. I'm stumped. I used the quotient rule. Heres my attempt of the inside derivative=
3t^2(t^3-3)-(t^3+3)3t^2/(t^3-3)^2
The numerator equals zero, so that times the first part is zero, leaving me with zero. I tried zero but it was wrong.
3.Alright, differentiate with respect to x right? I started by converting the radicals.
x^1/2+y^1/2=6
Derivative:
1/2x^(-1/2)+1/2y^(-1/2)y'=6
6 is a constant and equals zero, so I moved the x term over, then divided by 1/2y to get y' by it self:
(-.5x^(.5))/(.5y^(-.5))
Wrong. I didnt attempt the second part yet.
4. The derivative(so I've read) of e^x, is simply e^x. I converted the radical. Then applied the product rule.
1/2x^(-1/2)*e^x+x^(1/2)*e^x
Wrong. I think I might have not applied the chain rule to the last term. so If you take the derivative of e^x, it should be e^x? But that shouldn't matter because its still e^x. Right?
5. I took the 2nd power and applied to the the entire term.
(1-u/1+u)^2
Then used chain rule.
2(1-u/1+u)*(inside derivative)
inside=
-1(1+u)-(1-u)*1/(1+u)^2
-1-u-1+u/(1+u)^2
-2/(1+u)^2
final answer:
2(1-u/1+u)*(-2/(1+u)^2)
Still wrong. I'm not sure. This is what I typed: 2((1-u)/(1+u))*(-2)/(1+u)^2
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