Differential Eqn. of a 3rd order Filter

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The discussion revolves around deriving the differential equation from a given transfer function of a third-order Sallen-Key lowpass filter. The transfer function provided is H(s) = 15/(s^3 + 6s^2 + 15s + 15), and the user has formulated three voltage equations using Kirchhoff's laws for the circuit. There is uncertainty about the correctness of these equations and the next steps to derive the differential equation instead of simplifying to the transfer function. A suggestion is made that the transfer function can be converted to a differential equation by substituting s with d/dt. The conversation highlights the challenges of working with third-order circuits and the process of transitioning from transfer functions to differential equations.
Jaded1
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Hi guys :) I'm going through some prep. work for my modules in Fall and I've come across a question I'm having some difficulty with.

Homework Statement


The question has a transfer function for which I need to find the differential equation relating the output voltage and the input voltage.

Homework Equations


Transfer function: H(s) = 15/(s3 + 6s2 + 15s + 15)

The Attempt at a Solution


I created the above circuit using a 3rd order sallen-key lowpass filter as in this website:http://sim.okawa-denshi.jp/en/Sallenkey3Lowkeisan.htm. I then split the circuit into 3 parts - A,B,C.

I then deduced 3 voltage equations for the 3 nodes using kirchhoffs circuit laws as follows;

Va = (Va-Vin)/Z1 + (Va-Vb)/R2 + (Va-Vout)/Z2 = 0

Vb = (Vb-Va)/R2 + (Vb-Vout)/Z2 + (Vb-Vc)/R3 = 0

Vc = (Vc-Vb)/R3 + (Vc-0)/Z3 = 0

where Vc = Vout.

Are the above equations correct? I'm not very comfortable with 3rd order circuits as of yet, and am not sure if I got the equations right. I've gotten to this point, but after this I'm not sure what I need to do. If I simply the above equations I will get the transfer function, but that's not what I want to find, how do I proceed from here?
 
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If you're trying to derive the diff. eq. for the given transfer function, what are you doing with Sallen-Key filters?

A transfer function is readily transposed to a diff. eq. since s → d/dt. Take it from there ...
 

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