Differential Equation: Finding the Particular Solution for 4y'-4y=x*e^(3x)

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SUMMARY

The discussion focuses on solving the differential equation 4y' - 4y = x * e^(3x) to find its particular solution. The user proposes setting y equal to A * x * e^(3x) to derive y' and substitute back into the original equation. The method involves applying the operator D, leading to the characteristic equation 4(D-3)²(D-1)y = 0, which is then solved to eliminate extraneous solutions. This approach effectively outlines the steps necessary to find the particular solution for the given differential equation.

PREREQUISITES
  • Understanding of differential equations, specifically first-order linear equations.
  • Familiarity with the method of undetermined coefficients.
  • Knowledge of operator notation, particularly the use of D for differentiation.
  • Experience with solving characteristic equations.
NEXT STEPS
  • Study the method of undetermined coefficients in detail.
  • Learn about the application of the operator D in differential equations.
  • Research techniques for solving characteristic equations of higher-order linear differential equations.
  • Explore examples of finding particular solutions for non-homogeneous differential equations.
USEFUL FOR

Students studying differential equations, mathematics educators, and anyone looking to deepen their understanding of solving non-homogeneous linear differential equations.

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Homework Statement



4y'-4y=x*e^(3x)

Homework Equations



None

The Attempt at a Solution



The question is to find the particular solution

So I kinda know the way to solve this thing but the point is the start. I cannot figure out what will I set my y equal to. if it's only e^(3x) I will set my y=A*x*e^3x then find y' and substitute in the original equation to find the particular solution.
 
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4y'-4y=x*e^(3x)
4(D-1)y=x*e^(3x)
4(D-3)^2(D-1)y=0
solve
4(D-3)^2(D-1)y=0
then eliminate the extraneous solutions of

4(D-1)y=x*e^(3x)
 

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