Differential equation - seperation of variable

Homework Statement

e^3x dy/dx = 1/2y

The Attempt at a Solution

e^3x dy/dx = 1/2y

e^3x/dx = 1/2ydy

I can't determine the dirivitives for this equation can someone help me :)

The Attempt at a Solution

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Try rearranging the equation so that dx and dy are in the numerator instead of the denominator.

I tried that but i have the correct answer if y(0) = 4 the answer to the problem is

sqrt(16.33 - .33e^-3x)

if i rearange so dx and dy are in the numerator I get

dx/e^3x = dy/2y

Tom Mattson
Staff Emeritus
Gold Member
dx/e^3x = dy/2y
Nope, you're being careless with the algebra.

dx/e^3x = dy/2y
I am getting a different equation. Try rearranging again. :)

dx/e^3x = 2ydy

1/e^3x = y^2 + C

y= sqrt(C+e^-3x)

4= sqrt (C+ e^-3(0))

16 = C+1

C = 15

Thats what I keep getting I know im messing up somehwere

Double check your integration of 1/e^(3x).

Tom Mattson
Staff Emeritus
Gold Member
And try writing it as:

$$\exp^{-3x}dx$$

before you integrate.

And try writing it as:

$$\exp^{-3x}dx$$

before you integrate.
Thanks alot

$$\exp^{-3x}dx$$

$$\-.33exp^{-3x}$$

Tom Mattson
Staff Emeritus
Gold Member
Not quite, you're missing a negative sign. And instead of 0.33, you really should have 1/3. How would a rounded decimal emerge anyway? If you did the u-substitution that is required, the -1/3 should pop right out.

right :) thanks forgot the negitive in front. I realize it should be -1/3 i was just going with the answer my prof gave us :)

I came across another problem I cant solve

$$dy/dx=5y+1$$

$$dy/5y+1=dx$$

$$exp^{5y+1} = x$$

but i know this is incorrect can you point out where i am going wrong?