Differential Equation (Solution known, but I don't understand)

negatifzeo
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Homework Statement


In this problem, a function y= g(x) is described. Write a differential equation of the form "dy/dx=f(x,y) having the function g as it's solution (or one of it's solutions).

The line tangent to the graph of g at the point (x,y) intersects the x-axis at the point (x/2,0).



Homework Equations





The Attempt at a Solution


The solution is y'=2y/x. I'm having trouble seeing both why and how.
 
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The tangent passes through a point on the curve, call it (x,y) and has a slope y'. That tangent also passes through (x/2,0). Express y' by finding the slope of the line through the two points (x,y) and (x/2,0).
 
Thank you so much!
 
negatifzeo said:

Homework Statement


In this problem, a function y= g(x) is described. Write a differential equation of the form "dy/dx=f(x,y) having the function g as it's solution (or one of it's solutions).

The line tangent to the graph of g at the point (x,y) intersects the x-axis at the point (x/2,0).



Homework Equations





The Attempt at a Solution


The solution is y'=2y/x. I'm having trouble seeing both why and how.

Write the equation of line with m = g'(x), x0=x/2 and y0=0. Then try to recover that ODE.

AB
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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