Differential Equations-Finding Constants

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SUMMARY

The discussion focuses on the analysis of a differential equation represented by the linear function ay + b. The key point established is that at y = 3, the function transitions from positive to negative, indicating that the slope, represented by the constant "a," must be negative. This conclusion is drawn from the behavior of the function around the point y = 3, where it is shown that ay + b > 0 for y < 3 and ay + b < 0 for y > 3. Therefore, the negative slope confirms that "a" is indeed negative.

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  • Understanding of linear functions and their properties
  • Basic knowledge of differential equations
  • Familiarity with the concept of slope in mathematics
  • Ability to analyze sign changes in functions
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  • Study the properties of linear functions in detail
  • Explore the fundamentals of differential equations
  • Learn about the implications of slope in calculus
  • Investigate sign changes in functions and their graphical representations
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Students studying mathematics, particularly those focusing on differential equations, as well as educators and tutors looking to clarify concepts related to linear functions and their slopes.

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Differential Equations--Finding Constants

Homework Statement


I uploaded a pdf document, which contains the problem I am currently working on, namely, problem number 7

Homework Equations


The Attempt at a Solution


I am having particular difficulty with this portion of the solution:

"(ii) At y=3, the function ay+b changes from positive to negative
--> ay+b has a negative slope --> a is negative"

Why does "a" being negative follow from these facts? Also, why does a function change signs at y = 3?
 

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Two lines above, it was shown that ay + b > 0 when y < 3, and ay + b < 0 when y > 3. That literally means that it changes its sign at y = 3. And because it goes from positive to negative, it has to have a negative slope. Now this function is a simple straight line, so its slope = a, hence a must be negative.
 

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