What function do you know from calculus is such that its first derivative is a constant multiple k of itself? (Do not use the function f(x) = 0.)
The previous question asked what function was a derivative of itself - with the pretty easy answer of e^x. But I'm stuck on this one.
The Attempt at a Solution
To figure it out would involve finding the solution to something like:
y' = ky
Or at least that's the answer to the follow up question, which asks what differential equation this would satisfy. So it's something I just need to know.
I think I'm missing something very simple. I looked through all my calculus material and am at a loss to find such a function, though I have a feeling it's easier than I'm making it.