- #1
DryRun
Gold Member
- 838
- 4
Homework Statement
(9cos^2(x) + 4sin^2 (x)).dy/dx = 6
The attempt at a solution
Rearranging:
(1/6).dy = 1/(9cos^2(x) + 4sin^2 (x))
(1/6).dy = 1/((3cos(x))^2 + (2sin(x))^2)
L.H.S becomes y/6 after integrating.
The R.H.S. (denominator):
(3cos(x))^2 + (2sin(x))^2
I take out cos^2(x)
This leaves me with:
(9 + 4tan^2(x))
Then i use the standard integral formula for arctan
And i get: (1/3)arctan (2tanx/3)
Then I'm stuck...
(9cos^2(x) + 4sin^2 (x)).dy/dx = 6
The attempt at a solution
Rearranging:
(1/6).dy = 1/(9cos^2(x) + 4sin^2 (x))
(1/6).dy = 1/((3cos(x))^2 + (2sin(x))^2)
L.H.S becomes y/6 after integrating.
The R.H.S. (denominator):
(3cos(x))^2 + (2sin(x))^2
I take out cos^2(x)
This leaves me with:
(9 + 4tan^2(x))
Then i use the standard integral formula for arctan
And i get: (1/3)arctan (2tanx/3)
Then I'm stuck...