- #1

DryRun

Gold Member

- 838

- 4

**Homework Statement**

(9cos^2(x) + 4sin^2 (x)).dy/dx = 6

**The attempt at a solution**

Rearranging:

(1/6).dy = 1/(9cos^2(x) + 4sin^2 (x))

(1/6).dy = 1/((3cos(x))^2 + (2sin(x))^2)

L.H.S becomes y/6 after integrating.

The R.H.S. (denominator):

(3cos(x))^2 + (2sin(x))^2

I take out cos^2(x)

This leaves me with:

(9 + 4tan^2(x))

Then i use the standard integral formula for arctan

And i get: (1/3)arctan (2tanx/3)

Then i'm stuck...