(adsbygoogle = window.adsbygoogle || []).push({}); The problem statement, all variables and given/known data

(9cos^2(x) + 4sin^2 (x)).dy/dx = 6

The attempt at a solution

Rearranging:

(1/6).dy = 1/(9cos^2(x) + 4sin^2 (x))

(1/6).dy = 1/((3cos(x))^2 + (2sin(x))^2)

L.H.S becomes y/6 after integrating.

The R.H.S. (denominator):

(3cos(x))^2 + (2sin(x))^2

I take out cos^2(x)

This leaves me with:

(9 + 4tan^2(x))

Then i use the standard integral formula for arctan

And i get: (1/3)arctan (2tanx/3)

Then i'm stuck...

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# Homework Help: Differential equatn involving cos^2 and sin^2 in denominator

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