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**[SOLVED] Differentiation of displacement and time to get velocity**

A moving body is related to a fixed point by the displacement equation: s = 12( 1 - e^-t).

Assuming the body is moving in a straight line on a flat plain.

1. obtain an expression for the velocity after time t seconds.

2. obtain an expression for the acceleration also after t seconds

3. Calculate the time at which the velocity of the body is 6 ms-1.

So i know that s = v t. So v = s/ t and ds/dt = v

My attempt has gone round in circles because I am unsure of how exactly to differentiate it do I ignore the 12 first and diff. it, or times out the bracket then diff. it...? Too confused..