[SOLVED] Differentiation of displacement and time to get velocity A moving body is related to a fixed point by the displacement equation: s = 12( 1 - e^-t). Assuming the body is moving in a straight line on a flat plain. 1. obtain an expression for the velocity after time t seconds. 2. obtain an expression for the acceleration also after t seconds 3. Calculate the time at which the velocity of the body is 6 ms-1. So i know that s = v t. So v = s/ t and ds/dt = v My attempt has gone round in circles because I am unsure of how exactly to differentiate it do I ignore the 12 first and diff. it, or times out the bracket then diff. it....? Too confused..