# Differentiation Rules - Products~

1. Oct 18, 2009

### sp09ta

1. Suppose the curve f(x)=(x^4)+a(x^3)+b(x^2)+cx+d has tangent line when x=0 with equation y=2x+1, and a tangent line when x=1 with equation y=2-3x. Find a,b,c,d

2. d/dx f(x)g(x)=g*f+f*g

3. f`(x)=4x^3+3ax^2+2bx+c

x=0 y=2x+1 y=1 (0,1) is a point on f(x)
x=1 y=2x-3 y=-1 (1,-1) is a point on f(x)

This question really has me stumped... I just need a hint to get the ball rolling...

Last edited: Oct 18, 2009
2. Oct 18, 2009

### HallsofIvy

Okay, so f(0)= d= 1 and f'(0)= c= the slope of y= 2x+1.

so f(1)= ... and f'(1)= ...

3. Oct 19, 2009

### sp09ta

Ok, then f(1)=a+b+4=-1 and f'(1)=3a+2b+6=-3

so, a+b+5=0 and 3a+2b+9=0

then I isolate b in the first equation and sub it into the second to get:
3a+2(-a-5)+9=0
a=1

Then use a to find the value of b

So my values are: a=1, b=-6, c=2, d=1