Difficult : Calculate equivalent resistance of the circuit problem .

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Homework Help Overview

The discussion revolves around calculating the total equivalent resistance between points A and D in a circuit consisting of multiple 1-ohm resistors. Participants are attempting to analyze the circuit configuration and apply principles of resistance in series and parallel arrangements.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the configuration of resistors, with some suggesting that certain resistors are in parallel while others are in series. There is also a discussion about simplifying the circuit by removing resistors that are part of open circuits. Questions arise regarding the clarity of the circuit setup and the validity of the resistance calculations.

Discussion Status

Some participants have provided guidance on how to redraw the circuit for better clarity, while others express uncertainty about the calculations and configurations. There are differing interpretations of the circuit, and while some participants express agreement with certain approaches, there is no explicit consensus on the final equivalent resistance value.

Contextual Notes

There are indications that some participants are referencing the Wheatstone bridge concept, which may suggest a more complex understanding of the circuit's behavior. Additionally, the original poster has not been active for several years, which may affect the continuity of the discussion.

agoogler
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Homework Statement



Calculate the total equivalent resistance between A and D -
r8ibJ.png

( All resistors are 1 ohm )

Homework Equations


-


The Attempt at a Solution


The only thing I can see is that the two straight 1 ohm resistors are in parallel , giving 1*1/1+1= 1/2 resistance. But what next , please help !
 
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agoogler said:

Homework Statement



Calculate the total equivalent resistance between A and D -
r8ibJ.png

( All resistors are 1 ohm )

Homework Equations


-


The Attempt at a Solution


The only thing I can see is that the two straight 1 ohm resistors are in parallel , giving 1*1/1+1= 1/2 resistance. But what next , please help !

It's not clear what you mean by "the two straight 1 ohm resistors", but try this...

Since B and C are open circuits for this question, delete their respective 1 Ohm resistors. Then re-draw the circuit, with A at the top and D at the bottom. See if you can draw the resistors in a more normal configuration, using this simplification...
 
The only thing I can see is that the two straight 1 ohm resistors are in parallel , giving 1*1/1+1= 1/2 resistance.

There are no resistors directly in parallel so the above can't be right.

Do what berkeman said.
 
berkeman said:
It's not clear what you mean by "the two straight 1 ohm resistors", but try this...

Since B and C are open circuits for this question, delete their respective 1 Ohm resistors. Then re-draw the circuit, with A at the top and D at the bottom. See if you can draw the resistors in a more normal configuration, using this simplification...
Okay.
After deleting those two , I can see two pairs of resistors in series giving 2 each. Then these two 2 ohm resistors are in parallel , giving 1 ohm. Now these is in series with the remaining two 1 ohm resistors giving 3 ohm as the answer. Am I correct ?
 
I am sure that you are correct.
 
I agree.
 
According to Wheatstone bridge
Answer is 7/4 ohms that is 1.75 ohms
Am I correct ?
 
Kabir Nanda said:
According to Wheatstone bridge
Answer is 7/4 ohms that is 1.75 ohms
Am I correct ?
No. Show your work. Or better yet, start a new thread since this is a rather old thread (from 2013) and the Original Poster hasn't been logged in since 2015.
 

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