Difficult Coulombs Law questions

AI Thread Summary
To achieve equilibrium between two negative charges, -Q and -3Q, a positive charge must be placed between them, closer to -Q. The equilibrium condition involves calculating the forces acting on both negative charges and ensuring they balance. A coordinate system should be established, with one negative charge at x=0 and the positive charge at an arbitrary distance x. The distances between the charges must be carefully defined: the distance from -Q to +Q is x, and the distance from +Q to -3Q is L - x. Diagrams are essential for visualizing the configuration and understanding the relationships between the charges.
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Homework Statement


Q1.Two Charges, -Q and -3Q, are a distance l apart. The two charges are free to move but don't because there is a third charge nearby. What must the third charge be and where must it be placed for the first two to be in equilibrium?

Homework Equations


Coulombs Law: F = k.qQ/r^2


The Attempt at a Solution

 
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Well what do you think would be the first step to do? (if the two charges are -ve, would they repel or attract one another? Hence where should the third charge be placed such the charges do not move, between or outside the charges?)Draw the free-body diagram and put in the charges and distances.
 
rock.freak667 said:
Well what do you think would be the first step to do? (if the two charges are -ve, would they repel or attract one another? Hence where should the third charge be placed such the charges do not move?)

Yes I do know I must place a +ve charge between them, sorry I should have mentioned that however it's the magnitudes. It must be closer to the smaller charge.
 
Define a coordinate system and place the positive charge at an arbitrary distance from one of the negative charges. Call this distance x+. Can you write out the equilibrium condition for both negative charges in terms of x+?
 
ideasrule said:
Define a coordinate system and place the positive charge at an arbitrary distance from one of the negative charges. Call this distance x+. Can you write out the equilibrium condition for both negative charges in terms of x+?

So the distance between -Q and +Q is x - l? I'm lost with this one. you may have to elaborate.
 
It's l-x, because l is larger. I think you should draw out the configuration, placing all three charges along the x axis. For convenience, put one of the negative charges at x=0.
 
Basher said:
So the distance between -Q and +Q is x - l? I'm lost with this one. you may have to elaborate.

ah wait the distance between -Q and +Q is x. The distance between -Q and -3Q is L. And the distance between +Q and -3Q is L - x. Yes diagrams do help!
 
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