Diffraction on a body centered lattice, h+k+l even?

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Tom83B
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This is in my book:

[tex]exp[2\pi i(hx+ky+lz)][1+exp(\pi i(h+k+l))]=2exp[2\pi i(hx+ky+lz)]\cos^2[\frac{\pi}{2}(h+k+l)][/tex]

And in order for the cosine not to be zero, [tex]h+k+l[/tex] must be even when we want to see the reflection.

But I think that the result should be [tex]exp[2\pi i(hx+ky+lz)](2\cos^2[\frac{\pi}{2}(h+k+l)]+i\sin[\pi(h+k+l)])[/tex]
Why isn't the imaginary part there? My idea was that we only need the real part, but because we multiply two complex numbers, I can't do this because [tex]i^2=-1[/tex], can I?
 
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That does seem strange. What is this equation supposed to be anyway? For what purpose is the author converting the exponential to trig functions? Also, I recognize the (1+exp) factor as the structure factor for BCC, but I can't remember ever seeing it multiplied by a second exponential that way.
 
What is the sine of an integer multiple of pi?
 
Modulated said:
What is the sine of an integer multiple of pi?

Thank you very much :-)