Dilution: 18-2wt% Solution | Calculate Volume

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To dilute an 18 wt% solution to a 2 wt% solution, the initial concentration (C1) is 18% and the final desired concentration (C2) is 2%. The user aims for a final volume of 10 ml, leading to the equation (180 mg/ml)(X) = (2 mg/ml)(10 ml). After calculations, the user finds X to be 0.11 ml, which raises concerns about the accuracy of the dilution. Clarification is needed on whether 2 mg/ml corresponds to 2 wt%, as this may be causing confusion in the calculations.
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Hey,

I have a solution of 18 wt % (about 1g/ml) I want to make it into a solution of 2 wt % by diluting it with water. Using C1 V1 = C2 V2 could someone show me how to do it. I have tried but seem to be getting muddled somewhere.

Thanks!
 
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You need to know (or assume) initial (or final) volume.

Show what you did, we will start from there.

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Final desired volume 10ml

18% of 1g = 180mgC1 V1 = C2 V2
(180mg/ml)(X) = (2mg/ml) (10ml)
X = 2 (10) / 189
X = 0.11 ml <--- which seems too low
 
Why 2 mg/mL?

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I mean 2 wt percentage of the final solution
 
Perhaps that's what you mean, but does 2 mg/mL equal 2%?

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