Understanding the Dimension of a Variety in Algebraic Geometry

  • Thread starter Newtime
  • Start date
  • Tags
    Dimension
In summary, the concept of dimension of a variety in algebraic geometry can be defined as the smallest r such that the variety is isomorphic to projective r-space. However, this definition can be confusing and a more intuitive way of thinking about it is as the number of parameters needed to describe the variety locally or the number of algebraically independent rational functions on the variety. This definition is similar to the linear algebra definition of dimension, with the only difference being algebraic independence vs. linear independence. The term "variety" can also be confusing as it has different meanings in different languages, but in English it typically refers to an algebraic variety which is a zero set of polynomials.
  • #1
Newtime
348
0
This should be a simple question for anyone familiar with basic algebraic geometry, but the concept is getting the best of me. Basically I am unclear on the concept of dimension of a variety. I'm still stuck in the algebraic mindset that dimension is the (minimum) number of elements needed to span the space, but that doesn't seem to carry over. I have several books on the subject, and the most intuitive definition I've found was that the dimension of a variety is the smallest r such that the variety is isomorphic to projective r-space. However, this still has me confused: how does one compute/find/understand the dimension of a projective space? I know projective n space has a defined dimension, but I can't understand why...

In particular, one knows a smooth point of a variety is a point at which the dimension of the (affine) tangent space is locally constant. I can translate this back into the original vector space and see the dimension, but I don't see how this carries over into projective space.

I suppose I'm looking for a little intuition in this matter...

Also, I'm posting this in the "Topology and Geometry" forum also. Mods, if this is contrary to any rules, please remove whichever posting is in the wrong place, but since this is an algebraic geometry question, I figured it would be best to get both perspectives.

Thanks in advance.
 
Physics news on Phys.org
  • #2
A variety is a topological space with an atlas, that is, a set of charts, that is, a set of invertible homeomorphisms from the variety to R^n, with certain properties (for more detail, see any book on differential geometry, I recommend you the one by Flanders, or a more difficult one, Spivak). In easy and a bit improper words, a variety is a set which has n coordinates... n is called the dimension of the variety.
 
  • #3
Petr Mugver said:
A variety is a topological space with an atlas, that is, a set of charts, that is, a set of invertible homeomorphisms from the variety to R^n, with certain properties (for more detail, see any book on differential geometry, I recommend you the one by Flanders, or a more difficult one, Spivak). In easy and a bit improper words, a variety is a set which has n coordinates... n is called the dimension of the variety.

So what you're saying is similar to the notion of dimension in linear algebra. Informally, the dimension of a variety is the number of parameters needed to describe it locally? Or the number of "directions" we can go if we want to choose some point? I'll also have a look at the book you mentioned. Thanks for your reply.
 
  • #4
Petr Mugver said:
A variety is a topological space with an atlas, that is, a set of charts, that is, a set of invertible homeomorphisms from the variety to R^n, with certain properties (for more detail, see any book on differential geometry, I recommend you the one by Flanders, or a more difficult one, Spivak). In easy and a bit improper words, a variety is a set which has n coordinates... n is called the dimension of the variety.
There's some confusion in terminology. In many non-English languages (such as French), a cognate of the word "variety" is used to mean "manifold". In English, "variety" pretty much means "algebraic variety", which is a zero set of some set of polynomials.

I guess the usual definition is that if X is an irreducible algebraic variety, then dim(X) is the transcendence degree of the field k(X) of rational functions on X over k. That is, if dim(X) = n, then there are n algebraically independent rational functions on X, and any n+1 rational functions on X are algebraically dependent. (Elements f1,...,fr of k(X) are algebraically independent over k if and only if, given a polynomial P on r variables with coefficients in k, P(f1,...,fr) = 0 implies P = 0.) So this definition is pretty similar to the linear algebra definition of dimension, where the only real difference is algebraic independence vs. linear independence.

(By the way, this thread probably properly belongs in the Topology and Geometry forum, but since the discussion is here, let's keep it here.)
 
Last edited:
  • #5
adriank said:
There's some confusion in terminology. In many non-English languages (such as French), a cognate of the word "variety" is used to mean "manifold". In English, "variety" pretty much means "algebraic variety", which is a zero set of some set of polynomials.

Uhm you are right, I was talking about manifolds, and probably Newtime was talking about what you say (about which I know exactly nothing). I apologize: the confusion you mentioned about French also applies to italian! (my language)
 
  • #6
adriank said:
There's some confusion in terminology. In many non-English languages (such as French), a cognate of the word "variety" is used to mean "manifold". In English, "variety" pretty much means "algebraic variety", which is a zero set of some set of polynomials.

I guess the usual definition is that if X is an irreducible algebraic variety, then dim(X) is the transcendence degree of the field k(X) of rational functions on X over k. That is, if dim(X) = n, then there are n algebraically independent rational functions on X, and any n+1 rational functions on X are algebraically dependent. (Elements f1,...,fr of k(X) are algebraically independent over k if and only if, given a polynomial P on r variables with coefficients in k, P(f1,...,fr) = 0 implies P = 0.) So this definition is pretty similar to the linear algebra definition of dimension, where the only real difference is algebraic independence vs. linear independence.

(By the way, this thread probably properly belongs in the Topology and Geometry forum, but since the discussion is here, let's keep it here.)

Thanks for the reply. This looks like a good way of thinking of it.

I posted it in the topology and geometry section as well, but there are still no replies.
 

1. What is the dimension of a variety?

The dimension of a variety is a measure of its size and complexity. It can be thought of as the number of independent parameters needed to describe the variety.

2. How is the dimension of a variety calculated?

The dimension of a variety is calculated by finding the maximum number of independent elements in a basis for its coordinate ring. This is also known as the transcendence degree of the field of rational functions on the variety.

3. What is the relationship between dimension and degree of a variety?

The degree of a variety is the number of intersection points with a generic hyperplane in projective space, while the dimension is a measure of the variety's complexity. In general, a variety of degree d has dimension d-1.

4. Can the dimension of a variety change?

Yes, the dimension of a variety can change depending on how it is embedded in a projective space. For example, a curve may have different dimensions when considered as a plane curve or as a space curve.

5. How does the dimension of a variety affect its properties?

The dimension of a variety is an important factor in determining its properties. For example, a higher dimensional variety may have more complicated singularities and require more complex techniques for studying its geometry.

Similar threads

  • Linear and Abstract Algebra
Replies
14
Views
2K
  • Linear and Abstract Algebra
Replies
2
Views
3K
  • Linear and Abstract Algebra
Replies
7
Views
245
  • Linear and Abstract Algebra
Replies
3
Views
1K
  • Linear and Abstract Algebra
2
Replies
43
Views
5K
  • Linear and Abstract Algebra
Replies
4
Views
3K
Replies
3
Views
265
  • Linear and Abstract Algebra
Replies
5
Views
2K
  • Linear and Abstract Algebra
Replies
2
Views
1K
  • Linear and Abstract Algebra
Replies
3
Views
2K
Back
Top