Dimension of row/ column space

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Homework Help Overview

The discussion revolves around verifying that the row rank is equal to the column rank of a given matrix A = [1 2 1; 2 1 -1]. Participants are exploring the dimensions of the row space and column space.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of row reducing the matrix to row echelon form to find the rank. There are attempts to clarify the conditions under which the rows and columns are linear combinations of each other.

Discussion Status

Some participants have provided guidance on checking linear combinations of rows and columns, while others are confirming understanding of the concepts involved. There is an acknowledgment of a need for clarity in the statements made regarding linear combinations.

Contextual Notes

There is a focus on explicitly showing relationships between rows and columns to establish the ranks, with some participants questioning the accuracy of their interpretations.

jeffreylze
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Homework Statement



In the following exercises verify that the row rank is equal to the column rank by explicitly finding the dimensions of the row space and the column space of the given matrix.

A = [1 2 1 ; 2 1 -1]


Homework Equations





The Attempt at a Solution



All i can think of is just row reduce it to row echelon form and then find the rank of the matrix. How do i do it explicitly?
 
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1. Show that the rows of A are not linear combinations of each other, i.e. one is the multiple of the other.

2. Show that one column is the linear combination of the other 2 columns. Then show that the remaining 2 columns are not a multiple of the other.

then you've explicitly shown that the rank(A) = row rank (A) = column rank (A)
 
hokie1 said:
1. Show that the rows of A are not linear combinations of each other, i.e. one is the multiple of the other.

2. Show that one column is the linear combination of the other 2 columns. Then show that the remaining 2 columns are not a multiple of the other.

then you've explicitly shown that the rank(A) = row rank (A) = column rank (A)

Do you mean by one is NOT the multiple of the other?
 
You are quite correct. I did not proofread before submitting.
 
Okay, thanks. Now that make sense =D
 

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