I Dimensional Analysis: Torque, Moment of Inertia & Angular Acceleration

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The discussion focuses on the dimensional analysis of the equation T = Iα, which relates torque (T), moment of inertia (I), and angular acceleration (α). It highlights that the units for torque are expressed as N·m, while moment of inertia is in kg·m² and angular acceleration in rad/s². The key point is that when analyzing dimensions, the unit of force (N) can be derived from F = m·a, leading to N = kg·m/s². Additionally, the radian is considered dimensionless, simplifying the equation. Understanding these relationships clarifies how (kg·m·rad/s²) equates to Newtons.
Mikealvarado100
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Hi
The relation between torque, moment of inertia and angular acceleration is:
T=Ia
Have a look to it's units:
(N.m)=(kg.m^2).(Rad/s^2) >>>> N=kg.m.Rad/s^2
Please explain the equation Dimensionally. How (kg.m.Rad/s^2) is equal to N?
Thanks.
 
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Mikealvarado100 said:
Please explain the equation Dimensionally. How (kg.m.Rad/s^2) is equal to N?
Starting with F = m⋅a, the dimensions give N = kg⋅m/s2. Insert this in your equation and remember that "Rad" is dimensionless (arc length/radius gives m/m).
 
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