# Diode circuit with AC excitation source

• Engineering
• Gbox
In summary, when the input voltage, Vin, is equal to V, the left diode is forward biased and conducting while the right diode is reverse biased and removed from the circuit. The two capacitors in series create a potential divider circuit that divides the input voltage. This circuit assumes that the input voltage is much greater than the forward voltage of the diode.

## Homework Statement

Graph ##V_{out}##

## The Attempt at a Solution

When ##V_{in}=V## C1 is positive on the left and negative on the right, and C2 is negative on the the down side and positive on the upper side so there is no Vout?

Gbox said:
When Vin=VVin=VV_{in}=V C1 is positive on the left and negative on the right, and C2 is negative on the the down side and positive on the upper side so there is no Vout?

That's not correct.

For the moment let's assume that V is much greater than the forward voltage of the diode...

When Vin = +V the right hand diode is reverse biased (not conducting) so that can be temporarily removed. The left hand diode is forward biased (conducting) so replace it with a wire. Redraw the circuit to show this.

Then... Are you familiar with the "Potential Divider" circuit?

CWatters said:
That's not correct.

For the moment let's assume that V is much greater than the forward voltage of the diode...

When Vin = +V the right hand diode is reverse biased (not conducting) so that can be temporarily removed. The left hand diode is forward biased (conducting) so replace it with a wire. Redraw the circuit to show this.

Then... Are you familiar with the "Potential Divider" circuit?
Why is the left hand diode is conducting? the capacitors do not affect the voltage? do not they both charge to the same voltage and the diode is not conducting?

No they don't charge to the same voltage (unless they are same value). The two caps are in series.

This is what the circuit looks like when Vin transitions from 0 to +V (assuming +V >> Vd)...

## 1. What is a diode circuit with AC excitation source?

A diode circuit with AC excitation source is a circuit that uses a diode and an alternating current (AC) source to control the flow of electricity. The diode acts as a one-way valve, allowing current to flow in only one direction. The AC source provides a varying signal that can be used to control the diode's conductivity.

## 2. How does a diode circuit with AC excitation source work?

In a diode circuit with AC excitation source, the diode is connected in series with the AC source. When the AC current flows in one direction, the diode allows it to pass through, but when the current changes direction, the diode blocks it. This creates a pulsating current that can be used to power various electronic devices.

## 3. What are the applications of a diode circuit with AC excitation source?

A diode circuit with AC excitation source is commonly used in rectifier circuits to convert AC power into DC power. It is also used in electronic circuits for signal processing, voltage regulation, and power supply filtering. Additionally, it is used in radio and television receivers, as well as in power inverters for converting DC power to AC power.

## 4. What are the advantages of using a diode circuit with AC excitation source?

One of the main advantages of using a diode circuit with AC excitation source is its simplicity and low cost. It also has a high efficiency, as it only allows current to flow in one direction, reducing power loss. Additionally, it can handle high voltages and currents, making it suitable for a wide range of applications.

## 5. Are there any limitations to using a diode circuit with AC excitation source?

While a diode circuit with AC excitation source has many advantages, there are a few limitations to consider. One limitation is that it can only control the flow of electricity in one direction, so it is not suitable for bidirectional current. Additionally, the diode can generate heat, so proper heat dissipation measures must be taken to prevent damage to the circuit.