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We have a non-conducting beam with length L and uniform chargedistribution [tex]\lambda[/tex]. Half the beam is negativly charged and the other half positive.

The problem is to find the dipole moment of the beam.

I don't know how to proceed for a continous distribution like this, but I suppose it

is some kind of integral.

I found this integral at wikipedia, but I don't get the logic and what it reduces to in the

one-dimentional case. It seems like the dipolemoment is a function of r, but should'nt this be a property of the chargedistrobution alone?

[tex]\boldsymbol{p}(\boldsymbol{r}) = \int_{V} \rho(\boldsymbol{r_0})\, (\boldsymbol{r_0}-\boldsymbol{r}) \ d^3 \boldsymbol{r_0}[/tex]

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# Homework Help: Dipolemoment of charged beam

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