Direction of force exerted by ground for the ladder problem

AI Thread Summary
The discussion centers on the direction of the force exerted by the ground on a ladder leaning against a frictionless wall in static equilibrium. The hypothesis suggests that this force aligns with the ladder's angle, \theta, changing from vertical to horizontal as the ladder's position shifts. Participants emphasize the importance of analyzing forces and torques to confirm or disprove this hypothesis. The suggestion to solve the equations directly is made to clarify the relationship between the ladder's angle and the ground force direction. The inquiry highlights the complexities of static equilibrium in this classic physics problem.
ddcz
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This question pertains to the classic ladder-leaning-against frictionless wall scenario. The system is in static equilibrium. The ladder is thin and can be assumed to be made of a homogeneous material so that the center-of-mass lies at the geometric center.

The forces in this scenario is well-known, and diagrammed as follows. This type of problem can be solved by equating the sum of forces and torques to zero at any and all points, as is commonly done in static equilibrium problems.
Pic14.jpg


My question is: Is the direction of the force exerted by the ground on the ladder aligned with the ladder itself? That is, is the force exerted by the ground on the ladder in the direction \theta, as shown in the diagram?

This hypothesis seems plausible to me, because as theta becomes large (ladder is almost vertical), the force in question is also almost at 90 degrees. As theta approaches zero (ladder is almost horizontal), there is a large horizontal component, so the force is almost horizontal (to the right).

Could anyone confirm or disprove my hypothesis?
 
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ddcz said:
Is the direction of the force exerted by the ground on the ladder aligned with the ladder itself? That is, is the force exerted by the ground
Suppose it were. Consider moments about the mid point of the ladder.
 
ddcz said:
This question pertains to the classic ladder-leaning-against frictionless wall scenario. The system is in static equilibrium. The ladder is thin and can be assumed to be made of a homogeneous material so that the center-of-mass lies at the geometric center.

The forces in this scenario is well-known, and diagrammed as follows. This type of problem can be solved by equating the sum of forces and torques to zero at any and all points, as is commonly done in static equilibrium problems.
Pic14.jpg


My question is: Is the direction of the force exerted by the ground on the ladder aligned with the ladder itself? That is, is the force exerted by the ground on the ladder in the direction \theta, as shown in the diagram?

This hypothesis seems plausible to me, because as theta becomes large (ladder is almost vertical), the force in question is also almost at 90 degrees. As theta approaches zero (ladder is almost horizontal), there is a large horizontal component, so the force is almost horizontal (to the right).

Could anyone confirm or disprove my hypothesis?

Why not solve the equations and see for yourself?
 
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