Direction of Masses in Collision

AI Thread Summary
In elastic collisions, both kinetic energy and momentum are conserved, which is crucial for solving problems involving masses in motion. The discussion raises a question about the direction of movement for a 2M block after a collision, suggesting confusion about its behavior. The participant emphasizes the need to apply conservation laws to derive equations for the velocities of the involved masses. The conversation indicates a challenge in understanding the implications of these conservation principles in specific collision scenarios. Ultimately, clarity on these concepts is essential for accurately analyzing collision outcomes.
minimario
Messages
95
Reaction score
2

Homework Statement



L05Mj2M.png

2. Homework Equations


Elastic collision: KE conserved

The Attempt at a Solution



I don't think there's really anything to work out...why would the 2M block move right as well?
 
Physics news on Phys.org
Here's another problem on the same topic, that I can't decide
ioxOtmi.png
 
In both, use "conservation of momentum" and "conservation of energy" to get two equations to solve for the two velocities.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top