- #1

seahs

- 7

- 0

Assume the capacitor is connected to the voltage source using a resistor and the capacitor is 1F.

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- Thread starter seahs
- Start date

- #1

seahs

- 7

- 0

Assume the capacitor is connected to the voltage source using a resistor and the capacitor is 1F.

- #2

Carl Pugh

- 384

- 3

Homework ?

- #3

seahs

- 7

- 0

Homework ?

nope, just wondering what happens when the current flows into the voltage source

- #4

uart

Science Advisor

- 2,797

- 21

The energy gained by the voltage source is

The reduction in stored energy in the capacitor is

The energy lost is the difference of the above, which equals

Note that this energy loss is independent of the value of the resistor used to connect the two.

- #5

seahs

- 7

- 0

Vbis the battery (voltage source) voltage andVcis the initial capacitor voltage then :

The energy gained by the voltage source isVb*Q = Vb C ( Vc - Vb )

The reduction in stored energy in the capacitor is1/2 * C ( Vc^2 - Vb^2 )

The energy lost is the difference of the above, which equals1/2 * C (Vc - Vb)^2.

Note that this energy loss is independent of the value of the resistor used to connect the two.

Can the voltage source gain energy? what if the voltage source is like a non-rechargeable battery?

- #6

uart

Science Advisor

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- #7

sophiecentaur

Science Advisor

Gold Member

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Can the voltage source gain energy? what if the voltage source is like a non-rechargeable battery?

Yes - the 'voltage source' receives charge from the Capacitor. But, as stated above, half the energy is lost in a 'simple' connecting circuit. However, using a suitable inductor can ensure (virtually) no energy loss.

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